If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
To answer this, we need to first find the rate and the multiply it by 3. 840/12 = 70 miles per hour. Then multiply it by 3. 70*3=210 miles. Another way we can do it is that we can divide 840 by 4 because 12 hours / 4 = 3 hours. 840/4 = 210 miles.
Exponential form: F(x)= 3/125^x+1
Original voltage: 3/125 of a volt
I would estimate about 240
Answer:
The answer is on the screenshot
Step-by-step explanation:
The steps are also in 2nd screenshot and is on the website, just type in the thing you need solved. Hope i helped :)
