In a magnetized object, most of the domains point

The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about

gladu [14]

Answer: B. It is directed to the left.

Explanation:

Gravitational force is an attractive force, this is stated by Newton's law of Gravitation:

<em>"The force exerted between two bodies of masses m1 and m2 and separated by a distance is equal to the product of their masses and inversely proportional to the square of the distance"</em>

This means both m1 and m2 are mutually attracted.

Hence, if the force exerted on m1 by m2 is directed to the right, the force exerted on m2 by m1 must be logically <u>directed to the left.</u>

8 0

3 years ago

Find the magnitude and direction for 101m,60.0,85.0m

Crank

Answer:

magnitude = 161.3m, ∅ = 32.9°

Explanation:

Vector addition always works the same. Add two vectors by adding their respective components.

vector A: $\left[\begin{array}{c}85.0&0.0\end{array}\right]$

vector B: $101.0\left[\begin{array}{c} cos60.0&sin 60.0\end{array}\right] =\left[\begin{array}{c}50.5&87.5\end{array}\right]$

Adding vector A and B: $\left[\begin{array}{c}85.0&0.0\end{array}\right] +\left[\begin{array}{c}50.5&87.5\end{array}\right] = \left[\begin{array}{c}135.5&87.5\end{array}\right]$

The magnitude of any vector $\left[\begin{array}{c}a&b\end{array}\right]$ is given by the Pythagorean theorem:

$magnitude = \sqrt{a^2+b^2}$

In the case of the vector A+B:

$magnitude = \sqrt{135.5^2+87.5^2}$

The angle ∅ of the vector can by found by using trigonometric functions:

For instance, the angle ∅ for a vector $\left[\begin{array}{c}a&b\end{array}\right]$ is given by the equation:

$tan\phi= \frac{b}{a}$

The direction ∅ can be found by solving the trigonometric function.

In the example of vector A+B:

$tan\phi = \frac{87.5}{135.5}$

Solving for ∅:

$\phi = tan^{-1} (\frac{87.5}{135.5})=32.9$

4 0

3 years ago

What shape does a position vs. time graph have for an object in uniform acceleration? a. quadratic b. cubic c. inverse d. linear

umka2103 [35]

Here, If acceleration is uniform, change is velocity will be uniform, and position-time graph represents for velocity, so it would be Linear

In short, Your Answer would be Option D

Hope this helps!

6 0

4 years ago

If two automobiles have the same velocity do they have the same acceleration?

Mademuasel [1]

Nope not really one could have a faster acceleration than the other.

8 0

3 years ago

A current of 0.86 a flows through a copper wire 0.47 mm in diameter when it is connected to a potential difference of 15 v. how

likoan [24]

To calculate the length of the wire, we use formulas,

$R = \frac{V}{I}$ (A)

$R= \rho \frac{l}{A}$ (B)

Here, R is the resistance of the wire, I is the current flows through wire and V is potential difference. A is cross sectional area of wire and $\rho$ is the density of copper wire and is value, $\rho = 1.7\times 10^{-8} \Omega m$ .

Given $I = 0.86 A,V=15 V and r = \frac{0.47 mm}{2} =2.35 \times 10^{-4} m, V= 15 V.$

Substituting the values of I and V in equation (A ) we get,

$R=\frac{15V}{0.86A} = 17.44 \Omega$

Now from equation (B),

$l=\frac{R A}{\rho }$

Therefore,

$l= \frac{17.44\times\pi \times r^2 }{1.7\times 10^{8} \Omega m} \\\\ l= \frac{17.44\times 3.14 \times(2.35\times10^{-4}m)^2 }{1.7\times 10^{-8} \Omega m} = 177.9 m$

Thus the length of the copper wire is 177.9 m.

8 0

3 years ago