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yKpoI14uk [10]
4 years ago
15

If there was a decrease in consumer savings due to an increase in consumer spending with no increase in the money released into

circulation what will happen to the aggregate demand curve
Physics
1 answer:
lana66690 [7]4 years ago
6 0
The aggregate demand curve will also decrease. If supply is not high and there is no circulating income or monetary value that's happening in a particular market, then the demand of consumers will also go down. This is because the need for production is no longer necessary because there will be no consumers to purchase goods and services from the market.
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A plane startling from rest accelerates at 3 m/s Square. Calculate the increase in velocity after 25 sec
Tatiana [17]

Answer:

75 m/s

Explanation:

We can apply motion equations here

V = U + a * t

V =  velocity @ t time

U = initial velocity

a = acceleration

t = time taken

V = U + a * t

V = 0+ 3 * 25

V = 75 m/s

After  25 seconds , subjected to the given acceleration velocity is increased from 0 to 75 m/s

3 0
3 years ago
1. A jogger jogs 25 m East, stops to rest, then continues for 10 more meters
Komok [63]

Answer:

35m

Explanation:

25m + 10m = 35m east.

*(adding since it's in the same direction)

8 0
3 years ago
A football is thrown with an acceleration of 15 m/s^2 and a force of 13 N. What is its mass?
-Dominant- [34]
I believe it is b. Lmk if I’m wrong
7 0
2 years ago
Read 2 more answers
The magnitude of Earth’s magnetic field is about 0.5 gauss near Earth’s surface. What’s the maximum possible magnetic force on a
vampirchik [111]

Answer:

F = 1.5 \times 10^{-16} N

this force is 1.68 \times 10^{13} times more than the gravitational force

Explanation:

Kinetic Energy of the electron is given as

KE = 1 keV

KE = 1 \times 10^3 (1.6 \times 10^{-19}) J

KE = 1.6 \times 10^{-16} J

now the speed of electron is given as

KE = \frac{1}{2}mv^2

now we have

v = \sqrt{\frac{2 KE}{m}}

v = 1.87 \times 10^7 m/s

now the maximum force due to magnetic field is given as

F = qvB

F = (1.6\times 10^{-19})(1.87 \times 10^7)(0.5 \times 10^{-4})

F = 1.5 \times 10^{-16} N

Now if this force is compared by the gravitational force on the electron then it is

\frac{F}{F_g} = \frac{1.5 \times 10^{-16}}{9.1 \times 10^{-31} (9.8)}

\frac{F}{F_g} = 1.68 \times 10^{13}

so this force is 1.68 \times 10^{13} times more than the gravitational force

4 0
3 years ago
Work done in taking charge from one point of a conductor to is another point is called ​
Yuliya22 [10]

Answer:

⁸

Explanation:

electric potential

I think so

6 0
3 years ago
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