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yKpoI14uk [10]
4 years ago
15

If there was a decrease in consumer savings due to an increase in consumer spending with no increase in the money released into

circulation what will happen to the aggregate demand curve
Physics
1 answer:
lana66690 [7]4 years ago
6 0
The aggregate demand curve will also decrease. If supply is not high and there is no circulating income or monetary value that's happening in a particular market, then the demand of consumers will also go down. This is because the need for production is no longer necessary because there will be no consumers to purchase goods and services from the market.
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When hot and cold air meet, the hot air rises to the top. What causes the hot air to rise???
vekshin1
Hot air rises<span> because when you </span>heat air<span> (or any other gas for that matter), it expands. When the </span>air<span> expands, it becomes less dense than the </span>air<span>around it. The less dense </span>hot air<span> then floats in the more dense cold </span>air<span> much like wood floats on water because wood is less dense than water.</span>
3 0
3 years ago
How long it take a train to cover 630km having a speed of 30 km/hr​
noname [10]

Answer:

21 hours

Explanation:

well 30 x 20 = 600 than 21 = 630

4 0
3 years ago
Which body is found inside the solar system?
salantis [7]

Answer:

moon

Explanation:

Moon

4 0
3 years ago
Read 2 more answers
the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under i
Elanso [62]
Gravitational potential energy can be calculated using the formula:

PE_{grav} =mgh

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know. 
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it. 
PE_{grav} =mgh
PE_{grav} =(10kg)(3.7m/s^{2})(1m)
PE_{grav} =37J


7 0
4 years ago
A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass
Talja [164]

Answer:

a)1.93 kg-m^2

b) 1.45  kg-m^2

c) = 0

d) 1.15 kg-m^2

Explanation:

mass of the bar M = 4 kg

length of the bar = 2 m

mass of balls m1= m2= 0.3 kg

moment of inertia of bar I= \frac{ML^2}{12}

about an axis perpendicular to the bar through its center.

a) MOI of bar + 2×m×(L/2)^2

I= \frac{ML^2}{12}+ 2m\frac{L}{2}^2

now putting the values of m, M and L as above and solving we get

I= 1.93 kg-m^2

b) perpendicular to the bar through one of the balls

I=M\frac{L^2}{3} +mL^2

I=4\frac{2^2}{3} +0.3\times4^2= 1.45  kg-m^2

c) parallel to the bar through both balls

zero as the no mass distribution along the parallel to the bar through both balls.

d) parallel to the bar and 0.500 m from it.

I=(M+2m_1)\frac{1}{2}^2

putting values and solving we get

1.15 kg-m^2

4 0
4 years ago
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