How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 45 j of work?

Physics

1 answer:

bija089 [108]2 years ago

6 0

Here is your answer

$5 coulomb$

REASON :

We know that

Potential difference, V= W/q

where, W is work done

and, q is magnitude of charge

Given,

V= 9.0 v and W= 45 J

So,

using above relation, we get

9= 45/q

q= 45/9

q= 5 coulomb

HOPE IT IS USEFUL

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