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Lisa [10]
3 years ago
13

Solve for x. Assume that lines which appear tangent are tangent. Find x=

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

x=24?

Step-by-step explanation:

I'm rly not sure but my working is attached

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Plz help!!!! Need quick. 65 points
DanielleElmas [232]

Answer:

The area of the mat is 2/3 m^2

Step-by-step explanation:

Area of a rectangle is length times width or

A = l x w

8/9 x 3/4 =

24/36 =

2/3

4 0
3 years ago
Read 2 more answers
Find the radius or diameter of each circle with the given dimensions.<br><br> d=30 m
Alex_Xolod [135]

Answer:

r=94.2

Step-by-step explanation:

C=pi`d

C=3.14 multiplied by 30

C equals about 94.2

6 0
3 years ago
Which ordered pair is a solution to the equation y = 5x + 2?
Likurg_2 [28]
I’m geussing the answer would be A because an ordered pair of that is (2,8) but the only difference is it’s negative so A hope this helps
6 0
3 years ago
1a. Javier jogs 3/4 of a mile in 8 1/2 minutes.
Sergeu [11.5K]

Answer: 18/7

Step-by-step explanation: random.

7 0
3 years ago
PLEASE HELP!!! I don't understand it
Len [333]

Answer:

A

Step-by-step explanation:

This is exponential decay; the height of the ball is decreasing exponentially with each successive drop.  It's not going down at a steady rate.  If it was, this would be linear.  But gravity doesn't work on things that way.  If the ball was thrown up into the air, it would be parabolic; if the ball is dropped, the bounces are exponentially dropping in height.  The form of this equation is

y=a(b)^x, or in our case:

A(n)=a(b)^{n-1}, where

a is the initial height of the ball and

b is the decimal amount the bounce decreases each time.  For us:

a = 1.5 and

b = .74

Filling in,

A(n)=1.5(.74)^{n-1}

If ww want the height of the 6th bounce, n = 6.  Filling that into the equation we already wrote for our model:

A(6)=1.5(.74)^{6-1} which of course simplifies to

A(6)=1.5(.74)^5 which simplifies to

A(6)=1.5(.22190066)

So the height of the ball is that product.

A(6) = .33 cm

A is your answer

3 0
3 years ago
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