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3 years ago

A hydrocarbon with vapour density

Chemistry

1 answer:

Dafna1 [17]3 years ago

4 0

Answer:

the answer is C4H10 I hope I helped

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Which of the following would form a nonelectrolyte

Anastaziya [24]

This is answer open this image I am not sure is this wright

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3 years ago

What is the mass percentage of iodine (I2) in a solution containing 4.0×10−2 mol I2 in 130 g of CCl4? Express your answer using

musickatia [10]

Answer:

A. 7.2%

B. 8.6 ppm

Explanation:

<em>Part A</em>

First let's <em>calculate the mass of I₂</em>, using the known value of moles and the molecular weight (253.8 g/mol)

4.0x10⁻² mol I₂ * 253.8 g/mol = 10.152 g I₂

Mass percentage is calculated using the mass of I₂ and the total mass (mass of I₂ + mass of CCl₄)

Total mass = 130 + 10.152 = 140.152 g

Mass percentage I₂ = 10.152 / 140.152 * 100 = 7.2%

<em>Part B</em>

The concentration of Sr⁺² in ppm is calculated using the formula

mg Sr⁺² / L water

We're given the mass of Sr⁺² in grams, so now we <u>convert it into mg</u>:

8.2x10⁻³g * $\frac{1000mg}{1g}$ = 8.2 mg

Now to convert kg of water into L, we use the density of seawater (1050 kg/m³):

<em>Converting density</em>: 1050 $\frac{kg}{m^{3}}$ * $\frac{1m^{3}}{1000L}$ = 1.05 kg/L

Volume of one kilogram of water = 1kgWater ÷ 1.05 kg/L = 0.95 L

Finally we<u> calculate the concentration of Sr⁺²</u>:

8.2 mg / 0.95 L = 8.6 ppm

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3 years ago

What's the empirical formula of a molecule containing 18.7% element A, 16.3%

Makovka662 [10]

C I think it is c I think hope it issue

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3 years ago

A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.

nata0808 [166]

The equilibrium constant for this reaction at 350°C is determined as 5.85.

<h3>Concentration of each component</h3>

concentration of bromine, C(Br) = 0.6 mol/1 = 0.6

concentration of iodine, C(I) = 1.6 mol/1 = 1.6

<h3>Create an ICE table</h3><h3>What is ICE table?</h3>

An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.

ICE is an abbreviation that stands for initial, change, equilibrium.

Create ICE table for the reactants and products formed;

Br2(g) + I2(g) ↔ 2IBr(g)

I 0.6 1.6 0

C -1.19 -1.19 1.19

E 0.6 - 1.19 1.6 - 1.19 1.19

E = -0.59 0.41 1.19

<h3>Equilibrium constant </h3>

The equilibrium constant is calculated as follows;

KC = [IBr]²/[Br][I]

KC = (1.19²) / (0.59 x 0.41)

KC = 5.85

Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.

Learn more about equilibrium constant here: brainly.com/question/19340344

#SPJ1

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2 years ago

Which of the following correctly represents the radioactive decay of cesium-137?

Lelu [443]

The decay mode of cesium-137 is beta decay. This means that the cesium-137 decays into a beta particle and a nuclide with the same mass number, but with a charge number that is 1 more than that of cesium.

Therefore, this means Cs-137 decays into an electron and Barium-137, meaning the answer is choice 1.

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2 years ago