Answer:
5878 kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the calorimeter is zero.
Qcomb + Qcal = 0
Qcomb = -Qcal [1]
The heat absorbed by the calorimeter (Qcal) can be calculated using the following expression:
Qcal = Ccal . ΔT = 3.640 kJ/°C × 19.35°C = 70.43 kJ
where,
Ccal is the heat capacity of the calorimeter
ΔT is the difference in temperature
From [1],
Qcomb = - 70.43 kJ
Since this heat is measured at constant pressure, the molar enthalpy of combustion of cymene is:

Answer:
i think that sonoran toads would prosper and wood frogs would disappear
Explanation:
because of the provided information
Answer:
The noble gases have 8 valence electrons in their outermost electron shell. In other words, they have full out shells. These elements are highly stable.
Answer:
See explanation.
Explanation:
A. 2s is incorrect, the right arrow should be pointing downwards.
B. In 2p, the last box has 3 arrows. This is invalid. Each box can only store 2 arrows(electrons). The last arrow should be moved to a 3p orbital (new box).
C. In this one, the arrows switched directions (left is down and right is up). You could fix each box or just the last one (in 3p) to point downwards.