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Airida [17]
2 years ago
11

Don't understand question and don't know formula

Mathematics
1 answer:
zzz [600]2 years ago
7 0
The formula is (number of sides-2)*180 over number of sides

Each angle for hexagon is 120degree because
(6-2)*180 over 6 equals to 120
So p is 120
For q:
2q=180-120
2q=60
q=60 over 2
q=30
P+Q=120+30
=150
You might be interested in
The function h(x) is given below.
zavuch27 [327]

The inverse function will be h⁻¹(x) = {(–5, 3), (–7, 5), (–9, 6), (–12, 10), (–16, 12)}. Then the correct option is B.

<h3>What is inverse of a function?</h3>

Suppose that the given function is

f:X → Y

Then the inverse of the considered function will be

f⁻¹: Y → X

The function h(x) is given below.

h(x) = {(3, –5), (5, –7), (6, –9), (10, –12), (12, –16)}

Then the coordinate of the inverse function gets swapped.

h⁻¹(x) = {(–5, 3), (–7, 5), (–9, 6), (–12, 10), (–16, 12)}

Then the correct option is B.

Learn more about inverse function here:

brainly.com/question/19425567

#SPJ1

8 0
2 years ago
Can someone help please<br> what get doesn't show on these graphs
Julli [10]

Answer: The answer is no solution

Step-by-step explanation: if we try to get x to one side we subtract 2x from 2x on both sides and get 4 < 3 which is not true.

7 0
2 years ago
The teacher separated her class of twenty-eight students into two groups. One group has 4 more than twice as many students as th
wariber [46]
4+2x = x (x = student in smaller group)

4 + 2x + x = 28 (total # of students)
4+ 3x = 28
3x = 24
x = 8
8 students in the smaller group 
4 + 2(8) = 20 students in the larger group
8 0
3 years ago
A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of
navik [9.2K]

Answer:

A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects.

Step-by-step explanation:

6 0
2 years ago
Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

6 0
2 years ago
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