Answer:

Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form
, where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario
,
and
. Upon substituting these values in object's height function, we will get:

Therefore, the function for the height of the arrow would be
.
Answer:
-1/2
Step-by-step explanation:
Im not going to go into detail about how to compute sin30 and cos 30, but know that sine and cosine are just the ratios between the sides of a 30-60-90 triangle with a hypothenuse of 1.
With that being said:
sin^2 30 - cos^2 30
= (1/2)^2 - ((sqrt3)/2)^2
= 1/4 - 3/4
= -1/2
Answer:
Step-by-step explanation:
The answer is 5blocks to the right and 3 blocks up thank me LATER
Answer:
Step-by-step explanation:
50 dollars = ∉34
∉1 = Rs 150
Rs 382800 / 150 Rs per ∉ = 382800/150 ∉
=2552 ∉
50 dollars = ∉34 so 50/34 dollars = ∉
2552 ∉ × 50/34 dollar per ∉ = in the units the ∉ cancel out
∉ × dollar/∉ = dollars
(2552 × 50) / 34 = 3752.94 dollars <------------------
Here is another way of looking at the answer...........
Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ = note how the units cancel
= 382800 × (1/150) × (50/34) Rs × ∉/Rs × dollars/∉
= 3,752.94 dollars leaving only dollars in the numerator