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2 years ago

Plzzzzzzzz help me I really need it NOW.

Mathematics

2 answers:

valentinak56 [21]2 years ago

6 0

Answer:

2. 13

3. 20

4. 28

5. 27

6. 19 1/2

Step-by-step explanation:

Over [174]2 years ago

3 0

2. 13
3. 20
4. 28
5. 27
6. 13

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3 years ago

Erica baby sits for 4 1/2 hours and is paid $27.

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2 years ago

HELP!

maksim [4K]

Part A

$4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3$

So, the x-intercepts are $\boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}$

Part B

The vertex will be a minimum because the coefficient of $x^2$ is positive.

The x-coordinate of the vertex is $x=-\frac{-7}{2(4)}=\frac{7}{8}$

Substituting this back into the function, we get $f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}$

So, the coordinates of the vertex are $\boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}$

Part C

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

7 0

1 year ago

Whyyyyy do I suck so baddddddd

oksian1 [2.3K]

Okay, so first, the quadrants on a coordinate plane go counter clockwise.

2 | 1

__________|__________

3 | 4

(1/2, -1.8) Would be a little to the right of the y axis, and a little below the x axis.

So, your answer would be D) Quadrant IV

8 0

3 years ago