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Serjik [45]
3 years ago
10

Plzzzzzzzz help me I really need it NOW.

Mathematics
2 answers:
valentinak56 [21]3 years ago
6 0

Answer:

2. 13

3. 20

4. 28

5. 27

6. 19 1/2

Step-by-step explanation:

Over [174]3 years ago
3 0
2. 13
3. 20
4. 28
5. 27
6. 13
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WILL DO ABSOLUTELY ANYTHING FOR THIS ONE HELP ASAP TIMES
Rina8888 [55]

Given:

The graph of a function y=h(x).

To find:

The interval where h(x)>0.

Solution:

From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, h(x)>0 for x and x>3.6.

The function between x=0 and x=3.6 lies below the x-axis. So, h(x) for 0.

Now,

For -1, the graph of h(x) is above the x-axis. So, h(x)>0.

For 0, the graph of h(x) is below the x-axis. So, h(x).

For 1, the graph of h(x) is below the x-axis. So, h(x).

Only for the interval -1, we get h(x)>0.

Therefore, the correct option is A.

3 0
2 years ago
PLS I NEED HELP BRAINLIEST IS UP FOR GRABS
Gwar [14]

Answer:

(a) x > 4   (b) y < -2

Step-by-step explanation:

Domain is referring to the x-values while the range is referring to the y-values.

Since the function (the line) has a circle at the point (4, -2), the function will be exclusive at that coordinate.

The line goes to infinity for the x-values from 4, so you write x > 4 or ∞ > x > 4.

Similarly, the line goes to infinity for the y-values from -2, so you write y < -2 or -∞ < y < -2.

7 0
2 years ago
When listing the domain (and range), we<br> list the repeated numbers
svetoff [14.1K]

Answer:hope help

Step-by-step explanation:

Find the range by listing all the y values from the ordered pairs. Repeated values within the domain or range don't have to be listed more than once. In order for a relation to be a function, each x must correspond with only one y value.

8 0
2 years ago
Read 2 more answers
5/8 of 24 is equal to 15/7 of what number?
n200080 [17]

Answer:

fddsdfsd

Step-by-step explanation:

sesfdf

8 0
3 years ago
Read 2 more answers
In 2010, a city's population was 1,405,233 and it was decreasing at a rate of 1.1%. At this rate when will the city's population
frez [133]
The equation
                                            P(t) = 1405233 * (1 - 0.011)^(t)
models the population at t years after 2010. Then, when P(t) = 1,200,000, we have
                                 1200000 = 1405233 * (0.989)^t
                                  (0.989)^t = 1200000/1405233
                                                t = log(1200000/1405233)/log(0.989)
                                                t = 14.27 years
This means 14.27 years after 2010. Therefore, the answer to this question is 2024.
7 0
3 years ago
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