Well if you want to know 1.2 liters in milliliters the answer is 1200 milliliters and if you want to know 2000 milliliters in liters than the answer is 2 liters.
Answer:
B
Step-by-step explanation:
<u>This is a right triangle as shown by the right angle.</u>
- The side opposite the right angle is the hypotenuse, which is 9.
- The side opposite angle A is 3.
So we have the opposite of A and the hypotenuse.
The trigonometric ratio that relates opposite side to hypotenuse is SINE.

Since, we need angle A,
is A, opposite side is 3, and hypotenuse is 9, we substitute:

<em>To solve for the angle, we use our calculator and find the inverse sin of
:</em>

<em>Rounding to nearest tenth of a degree:</em>

B is the right choice.
Answer:
Step-by-step explanation:
Sine is positive while cotangent is negative. So this must mean cosine is negative since cos/sin = cot. In other words, cotangent is the ratio of cosine over sine.
Because cosine is negative and sine is positive, this places theta in quadrant 2
This is where x < 0 and y > 0. Recall that on the unit circle, x = cos(theta) and y = sin(theta).
The answer is choice B) quadrant II
Notation
I imagine that the expression you are asked to work with is:

When you use a keyboard it is customary to use "^" to denote an exponent is coming so you could have written: 3x^3y+15xy-9x^2y-45y just to be clear.
PART A
To factor out the GCF we are looking for the greatest factor among the terms. Looking at the coefficients (the numbers) the largest number they can all be divided by is 3 so we will pull out a 3. Notice also that each term has a y in it so we can pull out that.
This gives us:

To factor is to write as a product (something times something else). It undoes multiplication so in this case if you take what we got and multiplied it back you should get the expression we started with.
PART B
Start with the answer in part A. Namely,

. For now let's focus only on what is in the parenthesis. We have four terms so let's take them two at a time. I am separating the expression in two using square brackets.
![[( x^{3}+5x)]-[3 x^{2} -15]](https://tex.z-dn.net/?f=%5B%28%20x%5E%7B3%7D%2B5x%29%5D-%5B3%20x%5E%7B2%7D%20-15%5D)
Let's next factor what is in each bracket:
![[( x^{3}+5x)]-[3 x^{2} -15] = [x( x^{2} +5)]-[3( x^{2} +5)]](https://tex.z-dn.net/?f=%5B%28%20x%5E%7B3%7D%2B5x%29%5D-%5B3%20x%5E%7B2%7D%20-15%5D%20%3D%20%5Bx%28%20x%5E%7B2%7D%20%2B5%29%5D-%5B3%28%20x%5E%7B2%7D%20%2B5%29%5D)
Notice that both brackets have the same expression in them so now we factor that out:
![[x( x^{2} +5)]-[3( x^{2} +5)] = (x-3)( x^{2} +5)](https://tex.z-dn.net/?f=%20%5Bx%28%20x%5E%7B2%7D%20%2B5%29%5D-%5B3%28%20x%5E%7B2%7D%20%2B5%29%5D%20%3D%20%28x-3%29%28%20x%5E%7B2%7D%20%2B5%29)
Our original expression (the one we started the problem with) had a 3y we already pulled out. We need to include that in the completely factored expression. Doing so we get: