line segment ab has a slope 5/4 and contains point a(8,-7). what is the y-coordinate of point q(3,y) if qa is perpendicular to l ine ab? answer choices: a: y=-2 b: y=-3 c: y=1 d: y=3
1 answer:
U have a slope of 5/4...a perpendicular line will have a negative reciprocal slope...which means, the slope we need is -4/5. Now we use y = mx + b slope(m) = -4/5 (8,-7) -7 = -4/5(8) + b -7 = -32/5 + b -7 + 32/5 = b -35/5 + 32/5 = b -3/5 = b equation is : y = -4/5x - 3/5.....4x + 5y = -3 4x + 5y = -3....when x = 3 4(3) + 5y = -3 12 + 5y = -3 5y = -3-12 5y = - 15 y = -15/5 y = - 3 <===
You might be interested in
Mr. Renner will need 8 snowflakes. This is because 2/3 of three is 2 since it is 2 out of 3. Then, you multiply 2 times 4 since there are 4 groups. Then you get your answer of 8 snowflakes.
Answer:
7.89 till two decimal places.....
hope it helps
Answer: whats the question
Step-by-step explanation: put a image on the question
Answer:here ya go boys
Step-by-step explanation:
Answer:
what do you need help with? i can edit this later lol