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alina1380 [7]
3 years ago
10

16<−2(4x−4)

Mathematics
1 answer:
Contact [7]3 years ago
4 0

Answer:

x<-1 is the answer

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A tennis court has a length of (5x+7) and a width of (3x-3).
Oxana [17]
15x^2-15x+21x-21
15x^2+6x-21 is the answer
7 0
3 years ago
A.)Which two points should you use to find the equation of the model? Explain.
ikadub [295]

<u>Part a) </u>

we know that

to find the equation of the line, I will use the two points that are closest to the line


Let

A(1,14)

B(7,7)

<u>Part b) </u>

Find the slope

we know that

the formula to find the slope between two points is equal to

m=(y2-y1)/(x2-x1)

substitute

m=(7-14)/(7-1)

m=(-7)/(6)

m=-7/6=-1.167

<u>the answer part b) is</u>

the slope is m=-7/6=-1.167

<u>Part c)</u>

we know that

the equation of the line in point slope form is equal to

y-y1=m(x-x1)

use the point B (7,7)

y-7=(-7/6)*(x-7)

therefore

<u>the answer part c) is</u>

y-7=(-7/6)*(x-7)

<u>Part d) </u>

we know that

the equation of the line in slope-intercept for is equal to

y=mx+b

we have

y-7=(-7/6)*(x-7)

y=(-7/6)x+(49/6)+7

y=(-7/6)x+(91/6)

therefore

<u>the answer Part d) is</u>

y=(-7/6)x+(91/6) or y=-1.167x+15.167

3 0
4 years ago
Please Help!! 10 points! Brainliest answer
WINSTONCH [101]

Answer:

Its letter B

Step-by-step explanation:

6 0
4 years ago
Write 0.511 as a percent
Kazeer [188]

51.1 % is the answer.

3 0
3 years ago
Read 2 more answers
Quadratic Word Problems
Anit [1.1K]
4. Let the numbers be x - 2, x, and x + 2, where x is an odd number.
2(x² - 4) - 4x = (x + 2)² + 21
2x² - 8 - 4x = x² + 4x + 4 + 21
2x² - 4x - 8 = x² + 4x + 25
x² - 8x - 33 = 0
(x - 11)(x + 3) = 0

x = 11, or -3
When x = 11, x - 2 = 9, x + 2 = 13

When x = -3, x - 2 = -5, x + 2 = -1

Explanation: You are on the right track. However, rather than having three unknown variables, try to reduce your working out to one unknown variable. Since you know they are consecutive odd numbers, you can simply let x be the middle term and the other two be + and - 2, provided x is an odd number.

That will reduce your variable issues, and helps as the first and third provide a difference of two squares, and this works out very nicely.

Q5: is essentially the same process. Let your variables be something in the form of one unknown variable, and you should be okay from there. Let me know if you're stuck.
5 0
3 years ago
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