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jonny [76]
3 years ago
7

Balanced or Unbalanced CH4+4Ci2=CCi4+4HCi

Chemistry
1 answer:
Volgvan3 years ago
7 0

Answer:

balanced

Explanation:

its balance since all the elments add up on both sides

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To separate a mixture of iron filings and salt, the<br> most efficient method would be
CaHeK987 [17]

Iron filings can be attracted by the magnet whereas salt can not. So the mixture can be separated by a magnet

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3 years ago
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radioisotope actinium 225 has half life of 10 days, I begin with 16 kg of this isotope, how much will remain after 40 days?
Igoryamba
N(t)=N_{0}(\frac{1}{2})^\frac{t}{\tau_{_\frac{1}{2}}}}\\\\&#10;N_{0}=16kg\\&#10;t=40days\\&#10;\tau_{_\frac{1}{2}}}=10days\\\\\\&#10;N(t)=16kg*(\frac{1}{2})^{\frac{40}{10}}=16kg*\frac{1}{16}=1kg
3 0
3 years ago
Pls help me with this
Zina [86]

Answer:

[I_2]=[Br]=0.31M

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

I_2+Br_2\rightleftharpoons 2IBr

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}

Thus, we solve for x as show below:

\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M

Therefore, the concentrations of both bromine and iodine are:

[I_2]=[Br]=2.0M-1.69M=0.31M

Regards!

8 0
3 years ago
What is the oxidation state of co in [co(oh2)6]2?
Ahat [919]

Correct compound is [Co(H2O)6]^+3

The oxidation state of Co is +3

[Co(H2O)6]^+3

Let

 Co be x

 H2O = 0

 x + (0)6 = 3

 x = 3

What is oxidation state?

The oxidation state, commonly known as the oxidation number, is the potential charge that an atom would have if all of its bonds to other atoms were fully ionic. It describes the degree of atom oxidation within a chemical compound.The oxidation state may be positive, negative, or zero in theory.

The oxidation number, sometimes referred to as the oxidation state, is the total number of electrons that an atom gains or loses while uniting with another atom to form a chemical bond.

To learn more about oxidation state click the given link

brainly.com/question/8990767

#SPJ4

7 0
1 year ago
A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4(aq) +2Na
slega [8]
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l

n(NaOH)=v(NaOH)*c(NaOH)

n(H₂SO₄)=0.5n(NaOH)

c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)

c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l

The concentration of the H₂SO₄ is 0.418M.

4 0
3 years ago
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