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True [87]
3 years ago
15

Students are investigating the relationship between pressure and temperature in gases. They have blown up a balloon with carbon

dioxide from an air tank and
connected the balloon to a pressure gauge. The balloon is then submerged in ice or water baths at various temperatures in order to observe the pressure level
after several minutes. What is the flaw in the student's investigation, and how can the students improve their investigation to correctly determine the
relationship?
A The volume and density of the air in the balloon can change, therefore they need to use several different balloons at different volumes to account for
how density and volume affects pressure.
B. The volume of the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
C. The volume of the balloon can change, therefore they need to use several different balloons at different volumes to account for how volume atteots
pressure.
D. The volume and density of the air in the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

b

Explanation:

Alik [6]3 years ago
6 0
B: the volume of the balloon can change. Therefore they need to use several different balloons at different volumes to account for how volume atteots
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There are 43.2 g of carbon to 14.4 g of hydrogen in a sample of methane (CH4). What percent of 37.8 g of methane is carbon?
EastWind [94]

Using the law of constant proportions  which says that within the same compound, elements exist in fixed ratios. 

Therefore; we can use the ratio of total mass to the mass of carbon, to determine the amount of carbon in another sample.

Mass C / Mass CH4 = Mass C / Mass CH4

43.2 g / 57.6 g = Mass C / 37.8 g

Mass C = 37.8 g × 43.2 g / 57.6 g 

              = 28.35 g

Hence; the percentage of carbon will be; 

=(28.35/ 37.8 )× 100%

= 75 % 

Thus; 75% of 37.8 g of methane is carbon

8 0
3 years ago
If you have 30.O g of hydrogen gas burned in excess oxygen how many moles of water can you make
vladimir1956 [14]

Answer:

15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

amount of oxygen (O₂) = excess

moles of water = ?

Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

Reaction:

              2H₂  + O₂  -----------> 2H₂O

Now look at the reaction for mole ratio

             2H₂  + O₂  -----------> 2H₂O

             2 mole                       2 mole

So it is 2:2 mole ratio of hydrogen to water

As we Know

molar mass of H₂  = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

                  2H₂         +       O₂        ----------->    2H₂O

          2 mole (2 g/mol)                                 2 mole (18 g/mol)

                    4 g                                                     36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

                       4 g of H₂ ≅ 36 g of H₂O

                        30 g of H₂ ≅ X of H₂O

Do cross multiplication

                  X of H₂O =  30 g x 36 g / 4 g

                  X of H₂O =  270 g

Now convert grams of H₂O into moles

               No. of moles = mass in grams/molar mass

Put values in above formula

               No. of moles = 270 g / 18 (g/mol)

               No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

5 0
3 years ago
How many moles are in 12 gr of magnesium?
myrzilka [38]

Answer: 0.5 mole Mg

Explanation: solution:

12 g Mg x 1 mole Mg / 24 g Mg

= 0.5 mole Mg

5 0
3 years ago
Red blood cells contain an enzyme called carbonic anhydrase, which catalyzes the reversible reaction whereby carbon dioxide and
Dvinal [7]
Carbon o2 to bed the oxygen of the
3 0
3 years ago
10. pls pls help me
vagabundo [1.1K]

Answer:

2c2h2+502=4co2+H2O

Explanation:

this is the answer

8 0
3 years ago
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