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True [87]
3 years ago
15

Students are investigating the relationship between pressure and temperature in gases. They have blown up a balloon with carbon

dioxide from an air tank and
connected the balloon to a pressure gauge. The balloon is then submerged in ice or water baths at various temperatures in order to observe the pressure level
after several minutes. What is the flaw in the student's investigation, and how can the students improve their investigation to correctly determine the
relationship?
A The volume and density of the air in the balloon can change, therefore they need to use several different balloons at different volumes to account for
how density and volume affects pressure.
B. The volume of the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
C. The volume of the balloon can change, therefore they need to use several different balloons at different volumes to account for how volume atteots
pressure.
D. The volume and density of the air in the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

b

Explanation:

Alik [6]3 years ago
6 0
B: the volume of the balloon can change. Therefore they need to use several different balloons at different volumes to account for how volume atteots
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5 0
4 years ago
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What was the weight percent of water in the hydrate before heating?
DedPeter [7]
Data:

weight of water before heating = 0.349

weight of hydrate before heateing = 2.107

Formula:

Weight percent of water = [ (weight of water) / (weight of the hydrate) ] * 100

Solution:

Weight percent of water = [ 0.349 / 2.107] * 100 ≈ 16.6 %

Answer: 16.6%
3 0
4 years ago
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of
lianna [129]

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2     (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

8 0
3 years ago
Give the structure of the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane.
Fudgin [204]

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

what is free radical halogenation?

A substitution reaction in which a hydrogen atom is replaced with a halogen atom, via a free radical reaction mechanism. when this reaction is carrid out by bromine radical, it is called free radicle bromination. When bromine (Br{2}) treated with light (hν) it comes to homolytic cleavage of the Br-Br bond and give rise to bromine radicles.

free-radical bromination of 2,2,4−trimethylpentane

Bromination of an alkane includes the substitution of a bromine atom for a hydrogen atom. The following stages will be taken by 2,2,4-trimethylpentane during this reaction:

Initiation reaction:  The production of a bromine free radical requires the initiation of heat or light.

Br - Br ⇒ 2Br·

Propagation: This reaction relies heavily on hydrogen. This reaction is impossible if hydrogen is not present. Because tertiary free radicals are more stable than secondary and primary free radicals, they are favoured in this reaction.

Termination: The remaining free radical of bromide reacts with the tertiary free radical of 2,2,4-trimethylpentane to form 2-bromo-2,4,4-trimethylpentane.

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

To know more about free radical halogenation, check out:

brainly.com/question/13046867

#SPJ4

7 0
1 year ago
What volume of a 0.424 M CO2 solution are needed to produce 63.58 mL of 0.731 M solution of K2CO3?
cricket20 [7]

Answer:

Socratic app

Explanation:

it will help you

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3 years ago
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