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True [87]
3 years ago
15

Students are investigating the relationship between pressure and temperature in gases. They have blown up a balloon with carbon

dioxide from an air tank and
connected the balloon to a pressure gauge. The balloon is then submerged in ice or water baths at various temperatures in order to observe the pressure level
after several minutes. What is the flaw in the student's investigation, and how can the students improve their investigation to correctly determine the
relationship?
A The volume and density of the air in the balloon can change, therefore they need to use several different balloons at different volumes to account for
how density and volume affects pressure.
B. The volume of the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
C. The volume of the balloon can change, therefore they need to use several different balloons at different volumes to account for how volume atteots
pressure.
D. The volume and density of the air in the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

b

Explanation:

Alik [6]3 years ago
6 0
B: the volume of the balloon can change. Therefore they need to use several different balloons at different volumes to account for how volume atteots
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Explain how chemists overcome the problem of low yield In industry
mrs_skeptik [129]

High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

I hope this helps you.

8 0
3 years ago
Five more than two times the square root of a number is fifteen. What’s the number
ryzh [129]
The number is 25. The square root of 25 is 5 and 5x2 is 10 and then 10+5 is 15
7 0
3 years ago
Read 2 more answers
A solution of rubbing alcohol is 68.6 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 88.2 mL sample
KonstantinChe [14]


From the information given, the total volume of  rubbing alcohol is 88.2 ml

68.6 % of this volume is isopropanol. 

We will assume 88.2 ml represents 100% volume, so the volume of water will be 31.4 %

The volume of isopropanol is

68.6/100 x 88.2 → 0.686 × 88.2 = 60.505 ml

The volume of isopropanol is 60.5 ml.

Volume of water will be 88.20 - 60.5 = 27.7 ml

(27.7 / 88.2 × 100 = 31.4% )

Adding 60.5 ml of isopropanol to 27.7 ml of water to make up 88.2 ml will give 68.6 % v/v isopropanol to water  solution.



8 0
3 years ago
How many grams of acetylene are produced by adding water to 5.00 g CaC2?
Murljashka [212]

Answer:

2.03125g of acetylene

Explanation:

First thing's first, we have to write out the balanced chemical equation;

CaC2(s) + 2H2O(l) → Ca(OH)2(aq) + C2H2(g)

Water is in excess, so CAC2 is our limiting reactant. i.e it determines the amount of product that would be formed.

1 mol of CaC2 produces 1 mol of C2H2

In terms of mass;

Mass = Number of moles * Molar mass

where the molar mass of the elements are;

Ca = 40g/mol

C = 12g/mol

H = 1g/mol

CaC2 = 40+ (2*12) = 64g/mol

C2H2 =( 2 * 12) + ( 2 * 1) = 26g/mol

64g (1 * 64g/mol) of CaC2 produces 26g ( 1mol * 26g/mol) of C2H2

5g would produce x?

64 = 26

5 = x

Upon solving for x we have;

x = (5 * 26) / 64

x = 2.03125g

5 0
3 years ago
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