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True [87]
3 years ago
15

Students are investigating the relationship between pressure and temperature in gases. They have blown up a balloon with carbon

dioxide from an air tank and
connected the balloon to a pressure gauge. The balloon is then submerged in ice or water baths at various temperatures in order to observe the pressure level
after several minutes. What is the flaw in the student's investigation, and how can the students improve their investigation to correctly determine the
relationship?
A The volume and density of the air in the balloon can change, therefore they need to use several different balloons at different volumes to account for
how density and volume affects pressure.
B. The volume of the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
C. The volume of the balloon can change, therefore they need to use several different balloons at different volumes to account for how volume atteots
pressure.
D. The volume and density of the air in the balloon can change, therefore they need to use a rigid container such as plastic or metal to hold the air
Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

b

Explanation:

Alik [6]3 years ago
6 0
B: the volume of the balloon can change. Therefore they need to use several different balloons at different volumes to account for how volume atteots
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Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 V Cu2++2e−→Cu;E∘=0
Maru [420]

Answer:

Explanation:

To calculate the cell potential we use the relation:

Eº cell = Eº oxidation + Eº reduction

Now in order to determine which of the species is going to be oxidized, we have to remember that the more the value of the reduction potential is negative,  the greater its tendency to be oxidized is. In electrochemistry we use the values of the reductions potential in the tables for simplicity  because the only thing we need to do is change the sign of the reduction potential for the oxized species .

So the species that is going to be oxidized is the Aluminium, and therefore:

Eº cell = -( -1.66 V ) + 0.340 V =  5.06 V

Equally valid is to write the equation as:

Eº cell = Eº reduction for the reduced species - Eº reduction for the oxidized species

These two expressions are equivalent, choose the one you fell more comfortable but be careful with the signs.

3 0
3 years ago
What would A be? HELP ASAP
Minchanka [31]
Si has 4 available elections. Each Cl has 7.
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What was the original element formed moments after the Big Bang? What then created higher order elements?
Semmy [17]
Hydrogen (H) was first, followed by helium (He).
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when hydrogen atom absorbs a photon, and an electron moves level 1 to level 2, what happens to the energy of the atom?
pychu [463]

Answer:

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon).

Explanation: pls mark brainliest :))

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2 years ago
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