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2 years ago

Factorise: 4x^2+4xy+y^2-2^2

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

5 0

Answer:

Step-by-step explanation:

4x^2 + 4xy + y^2 = (2x + y)^2

and if we assume that 2x + y = A and because 4 = 2^2

A^2 - 2^2 = (A-2)*(A+2) .

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Step-by-step explanation:

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3 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0

3 years ago

I need help really badly please help me I’ll give brainiest

Mashutka [201]

Answer:

75%

Step-by-step explanation:

15+15+25+5=60

15/60=25%

100%-25% = 75%

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2 years ago

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3 years ago

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sesenic [268]

Multiply the first equation by -2

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2 years ago

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