Answer: 175.35g
Explanation: A 3 M solution has 3 moles of solute per litre.
The mass of one mole of NaCl equals the MW of NaCl MW = 35.45 + 23 =58.45 g/mol
The mass of 3 moles is 58.45 g/mol ×3 mol=175.35 g NaCl or 200 g rounded to one sigfig.
Answer: The rate of appearance of 
is 
Explanation:
Rate of a reaction is defined as the rate of change of concentration per unit time.
Thus for reaction:
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
![Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}](https://tex.z-dn.net/?f=Rate%3D-%5Cfrac%7B1d%5BI%5E-%5D%7D%7B5dt%7D%3D%2B%5Cfrac%7Bd%5BI_2%5D%7D%7B3dt%7D)
Given: ![-\frac{d[I^-]}{dt}]](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BI%5E-%5D%7D%7Bdt%7D%5D)
= 
![+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls](https://tex.z-dn.net/?f=%2B%5Cfrac%7Bd%5BI_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B3d%5BI%5E-%5D%7D%7B5dt%7D%3D-%5Cfrac%7B3%7D%7B5%7D%5Ctimes%202.4%5Ctimes%2010%5E%7B-3%7Dmol%2FLs%3D1.44%5Ctimes%2010%5E%7B-3%7Dmol%2FLs)
The rate of appearance of is
Answer:
P₂ = 20.5 torr
Explanation:
Given data:
Volume of tank = 15.0 L
Pressure of tank = 8.20×10⁴ torr
Final volume of tank = 6.00×10⁴ L
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
8.20×10⁴ torr × 15.0 L = P₂ × 6.00×10⁴ L
P₂ = 8.20×10⁴ torr × 15.0 L / 6.00×10⁴ L
P₂ = 123×10⁴ torr.L/ 6.00×10⁴ L
P₂ = 20.5 torr
We need to set up an I.C.E chart as follows:
CO H20 CO2 H2
<span>I 0.35 0.40 0 0 </span>
<span>C .35-x 0.40-x x x </span>
<span>E 0.19 0.40-x x x
</span>
We have 0.35 mol of CO at the start and 0.19 remaining. This means that x=0.35-0.19 >> 0.16
<span>Now substitute in 0.16 in your Ke equation. </span>
<span>Just in case you're having trouble with that: </span>
<span>Kb= [Products]/[Reactants] = ([CO][H2O])/([CO2][H2])
</span>
Therefore, the constant of equilibrium would be equal to 0.56.
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
