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lianna [129]
3 years ago
12

Fill in the coefficients that will balance the following reaction:

Chemistry
2 answers:
Tema [17]3 years ago
6 0

Answer:

a0=1

a1=6

a2=2

a3=3

Explanation:

We have to start with the <u>reaction</u>:

Cr_2(SO_4)_3~+~AgNO_3~->~Cr(NO_3)_3~+~Ag_2SO_4

We have to start with "Cr". If we want to balance <u>Cr</u> we have to obtain <u>2 on both sides</u>. Therefore we have to add a "2" on the right side, so:

Cr_2(SO_4)_3~+~AgNO_3~->~2Cr(NO_3)_3~+~Ag_2SO_4

Then we can balance "NO_3" as a whole. We have <u>6 on the right</u>, we have to have the same amount on the left side, so:

Cr_2(SO_4)_3~+~6AgNO_3~->~2Cr(NO_3)_3~+~Ag_2SO_4

Then we can balance "Ag". We have 6 on the left, so we have to have the same amount on the right if we already have 2 we have to put a · in front (on the right side) to obtain in <u>total 6</u>, so:

Cr_2(SO_4)_3~+~6AgNO_3~->~2Cr(NO_3)_3~+~3Ag_2SO_4

Finally, when we add this last number the SO_4 we will have 3 on both sides. Therefore the reaction is <u>already balanced</u>.

Kay [80]3 years ago
3 0

Answer

Explanation:

can you please put it in boxes so i can find out the answer

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