(y+20)=1(x+10); First, we can find the slope by using the equation y2-y1/x2-x1.
-9+20/1+10 (Accounting for double negatives).
11/11 = 1
The slope of the equation is 1, now we just need to pick a set of points from which we derived the slope from (doesn't matter which) as y1 and x1 in the point-slope equation. (y-y1)=m(x-x1)
Your final answer can either be (y+20)=1(x+10) or (y+9)=1(x-1) but in the context of this question it is (y+20)=1(x+10)
5 * (2 + 4)
5 * 2 + 5 * 4 (the distributive property)
5 * 6 (order of operations)
For the first equation, I put it in y=mx+b form, so y=-3x-9
the second one is x=4
hope i helped
To find the perpendicular line, we need to find the negative inverse slope.
y = -1/2x - 2
This line also passes through the point since both have the y intercept / value of -2.
Hope this helps!
Pretty sure it’s 4 idk tho this is a tough one. Hahahaha
