Please help me out with this question.<br>much appreciation. Thanks.

Inessa [10]

Lateral is 13.8cm
Total surface area is 32cm

7 0

3 years ago

one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt

In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

$\text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A$

⇒ $\text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A$

$= \frac{3-1}{3} A$

$= \frac{2}{3} A$

$\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B$

⇒ $\text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B$

But, Again according to the question,

The total population that claims that they are from A = one half of the total population of A and B.

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B$

⇒ $\frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B$

⇒ $\frac{1}{6} A = \frac{1}{4} B$

⇒ $A =\frac{6}{4}B$

⇒ $\frac{A}{B} =\frac{3}{2}$

8 0

3 years ago

A right cylinder has a radius of r inches and height of 2r inches.

Bess [88]

Answer:

the volume is $6.28r^{3}$ $in^{3}$

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cylinder.

Given data

Volume v = ?

Radius r = r in

Height h= 2r in

We are expected to solve for the volume of a cylinder, given the above data we can substitute it in the formula for volume of a cylinder to obtain our result

we know that the expression for the volume of a cylinder is

$v= \pi r^{2} h$

$v= 3.142*r^{2} *2r\\v= 3.142*2r^{3} \\v= 6.28r^{3} in^{3} \\$

Hence the volume in terms of the radius is $6.28r^{3}in ^{3}$

6 0

3 years ago

"The manager for State Bank and Trust has recently examined the credit card account balances for the customers of her bank and f

yuradex [85]

Answer:

a

$P(X = 4 ) = 0.1876$

b

$P(X \le 4) = 0.8358$

Step-by-step explanation:

From the question we are told that

The proportion that has outstanding balance is p = 0.20

The sample size is n = 15

Given that the properties of the binomial distribution apply, for a randomly selected number(X) of credit card

$X \ \ ~ Bin (n , p )$

Generally the probability of finding 4 customers in a sample of 15 who have "maxed out" their credit cards is mathematically represented as

$P(X = 4 ) = ^nC_4 * p^4 * (1 - p)^{n-4}$

=> $P(X = 4 ) = ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}$

Here C stand for combination

=> $P(X = 4 ) = 0.1876$

Generally the probability that 4 or fewer customers in the sample will have balances at the limit of the credit card is mathematically represented as

$P(X \le 4) = [ ^{15}C_0 * (0.20)^0 * (1 - 0.20)^{15-0}]+[ ^{15}C_1 * (0.20)^1 * (1 - 0.20)^{15-1}]+\cdots+[ ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}]$