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Let 
be the point on the ground to with the 18 foot guy is anchored and 
the point on the ground to with the 21 foot guy is anchored.
We can conclude that the <span>the two wires at the points where they are anchored are 21 feet apart. Check the procedures in the picture attached.</span>
We can conclude that the <span>the two wires at the points where they are anchored are 21 feet apart. Check the procedures in the picture attached.</span>
In order to solve this problem, you need to use a geometric series:
where:
a₁ = first term of the series = 36000
r = common rate = 10% raise, therefore 1.10
n = number of terms = 5
Therefore,
<span>
= 219783.60 $
Luke's total earnings in five years are <span>219783.60 $.</span>
</span>
where:
a₁ = first term of the series = 36000
r = common rate = 10% raise, therefore 1.10
n = number of terms = 5
Therefore,
<span>
= 219783.60 $
Luke's total earnings in five years are <span>219783.60 $.</span>
</span>
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> , which is your final answer.</u>