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Verizon [17]
3 years ago
9

ALEGBRA 1 ! help. me. please. this. is. so. hard. i dont. understand it.

Mathematics
1 answer:
ANEK [815]3 years ago
8 0

Answer:

Part a) to find the maximum height of the snowball, you have to differentiate the function. Therefore you get ----> dh/dt= -32x-8 . Now equate this to zero and solve for x. x= (-1)/4 now sub this value in to find h(x) [note: i'm talking about the original function] . I got h max = h((-1)/4) = 9 which is the max height.

Step-by-step explanation:

I'm not too sure about the other questions. Sorry

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Maysoun drove 1116 kilometers in 12 hours. At the same rate, how long would it take her to drive 651 kilometers?
Lilit [14]

Answer:

7 hours

Step-by-step explanation:

12hrs=1116kms

1hr=1116÷12

1hr=93kms

Xhrs=651kms

Xhrs=(651÷93) ×1

=7×1

=7hrs

7 0
2 years ago
PLS PLS PLS I NEED HELP FAAAAAAAASSSSST GIVING BRAINLIEST TO QUICKEST CORRECT ​
ElenaW [278]

Answer:

c hope this helps

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Given: <br> ΔABC, m∠C = 90º, m∠B = 30º<br> CM - angle bisector<br><br> Find: m∠AMC
SashulF [63]

Answer:

75°

Step-by-step explanation:

1. Consider right triangle ABC. In this triangle

m∠C = 90º and CM - angle bisector.

If CM is angle C bisector, then

m∠ACM = m∠MCB = 45º

2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then

m∠MCB + m∠CBM + m∠BMC = 180°,

m∠BMC = 180° - 45° - 30°

m∠BMC = 105°

3. Angles AMC and BMC are supplementary angles, so

m∠AMC + m∠BMC = 180°

m∠AMC = 180° - 105°

m∠AMC = 75°

3 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
Which factored form is equivalent to the expression x^2 + 5x + 4? A) (x + 2)(x + 3) B) (x + 4)(x + 1) C) (x + 5)(x − 1) D) (x −
777dan777 [17]
<h3>Answer ↓</h3>

option B.

Calculations ↓

First, let's think of two numbers so that :

  • if we multiply these numbers, we'll get 4
  • if we add these numbers, we'll get 5

These numbers are :

4 and 1

Plug these numbers here :

(x+4) (x+1)

So the correct factored form of this expression is

Option B) (x+4)(x+1)

\footnotesize\text{hope\:helpful~}}

7 0
2 years ago
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