Answer:
6x^2-48x-29
Step-by-step explanation:
Answer:
Therefore $98 is be charged a bus containing 30 people.
Step-by-step explanation:
Given that,
A state park charges an entrance fee based on the number of people in vehicle.
Let the entry fee for the vehicle be E and entry fee for each person be x.
Then
C= E+(P×x)
C= Total charge in $
E= entry fee for a vehicle
P=No. of person
x= Entry charge per person.
Given A car containing 2 people charged $14
C=$14, P=2
∴14= E+(2× x)
⇒E+2x=14.....(1)
Again A car containing 4 people charged $20
C=$20, P=4
∴20= E+(4× x)
⇒E+4x=20.....(2)
Subtract (1) from (2), we get
E+4x-(E+2x)= 20-14
⇒E+4x-E-2x=6
⇒2x=6
⇒x=3
Putting the value of x in equation (1)
E+(2×3)=14
⇒E=14-6
⇒E=8
Therefore E=$8 and x=$3
Next we check whether our assumption is correct or wrong. Putting the value of E and x for third case
Here P= 8
Therefore C= E+(P×x)
= 8+(8× 3)
=8+24
=$32
Therefore our assumption is correct.
Now C=? , P= 30
The charged for the 30 people is
C= $[8+(30×3)]
=$[8+90]
=$98
Therefore $98 is be charged a bus containing 30 people.
Answer:
v=6
Step-by-step explanation:
2v is positive so keep it
then 2v=12
v=6
Answer:
Step-by-step explanation:
The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have
P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2
or you can find the probability of getting two odds or two evens and subtract that from 1
P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4
P(EO)=1-1/4-1/4=1/2
