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2 years ago

Drag and drop each organic compound's role in nutrition next to the its name. Not all tile will be used.

Physics

1 answer:

iogann1982 [59]2 years ago

3 0

Answer:

Carbs Provide Your Body With Energy

Proteins help your body build new cells, repair old cells, create hormones and enzymes, and keep your immune system healthy

Calcium is a mineral that people need to build and maintain strong bones and teeth. It is also very important for other physical functions, such as muscle control and blood circulation.

Stored body fat is called adipose tissue. Stored fat not only provides an energy reserve, but also cushions and protects internal organs. In addition, stored fat insulates the body and helps prevent heat loss in cold weather

Explanation:

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If someone looks far enough into space, they should be able to see the beginning of the universe true of false

kodGreya [7K]

The answer is no, it would be impossible to see the beginning of the universe

8 0

2 years ago

GIZMO

CaHeK987 [17]

It is A or D but I believe A

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2 years ago

Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,

klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble= $2\hat{i}-3\hat{k}$ N

Position vector= $r=0.5\hat{j}-2\hat{k}$ m

a.We have to find the resulting torque on the pebble about origin.

Torque= $r\times F$

Substitute the values then we get

$Torque= (0.5j-2k)\times (2i-3k)$

Torque= $-k-1.5i-4j$ N-m

By using $i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0$

b. $r=2i-3k$

$r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k$

Torque about point (2,0,-3)

$\tau=(-2i+0.5j+k)\times (2i-3k)$

$\tau=-6j-k-1.5i+2j=-1.5i-4j-k$ N-m

6 0

2 years ago

You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 16.0 m above the ground, it is tr

Morgarella [4.7K]

Answer:

The final speed of the stone as it lift the ground is 23.86 m/s.

Explanation:

Given that,

Force acting on the rock, F = 3 N

Distance, d = 16 m

Initial speed of the stone, u = 22 m/s

We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :

$W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s$

So, the final speed of the stone as it lift the ground is 23.86 m/s.

4 0

2 years ago

Find the total displacement of a mouse that travels 1.0 m north and then 0.8 m south.

andreev551 [17]

North: 1m
South: 0,8m

Direction:

1m>0,8m

so mouse moved north

Distance:

1m-0,8m=0,2m

so mouse traveled 0,2m

Answer: The mouse moved 0,2m north.

"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."

Regards M.Y.

3 0

2 years ago