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Serggg [28]
2 years ago
11

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1

869 N to the right. What is the acceleration of the crate?
a=(6.0 or 6.00 or 8.10 or 8.1)=m/s^2
Physics
1 answer:
Daniel [21]2 years ago
6 0

The acceleration of the steel crate, given the data from the question is 6.0 m/s²

<h3>How to determine the net force</h3>
  • Force to the left (Fբ) = 480 N
  • Force to the right (Fᵣ) = 1869 N
  • Net force (Fₙ) = ?

Fₙ = Fᵣ - Fբ

Fₙ = 1869 - 480

Fₙ = 1389 N

<h3>How to determine the acceleration</h3>
  • Mass (m) = 230 Kg
  • Net force (Fₙ) = 1389 N
  • Acceleration (a) = ?

Fₙ = ma

Divide both sides by m

a = Fₙ / m

a = 1389 / 230

a = 6.0 m/s²

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

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How long does it take for a truck accelerating at 1.5 m/s^2 to got from rest to 75 km/hr
Free_Kalibri [48]

Answer:

t = 13.9s

Explanation:

u = 0 m/s

v = 75 km/h

= 20.83 m/s

a = 1.5 m/s²

Using

v = u + at

20.83 = 0 + 1.5t

t = 13.9s

6 0
4 years ago
A cord of negligible mass runs around two massless, frictionless pulleys. A canister with mass m = 20 kg hangs from one pulley.
photoshop1234 [79]

(a) 196 N

The equation of the forces on the side of the cord where the force F is applied is:

F-T=0 (1)

where T is the tension in the cord.

On the other side of the cord, the equation of the forces on the canister is

T-mg = ma (2)

where

m = 20 kg is the mass of the canister

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration

From (1),

T=F

Substituting into (2),

F-mg = ma\\F=m(g+a)

We want the canister to move at constant speed, so

a = 0

And therefore:

F=mg=(20)(9.8)=196 N

b) 2.0 cm

The cord is inextensible, this means that the acceleration of its parts are the same. Therefore, the acceleration of the free end must be the same as the acceleration of the canister: and this means that the two parts also cover the same distance in the same time.

Therefore, the free end of the cord must be moved exactly the same as the canister, by 2.0 cm.

c) 3.92 J, the same

The work done by the tension in the cord is

W_T = T d

where

T is the tension

d = 2.0 cm = 0.02 m is the displacement

As we said in part (a), the tension in the cord is equal to the force applied to the free end:

T = F

So

T = 196 N

Therefore, the work done by the tension is

W=(196)(0.02)=3.92 J

And since the force applied (F) is the same, then the work done by you when pulling the cord is exactly the same.

(d) -3.92 J

The weight of the canister is

F_g = mg =(20 kg)(9.8 m/s^2)=196 N

However, the direction of the force of gravity is opposite to the displacement. Therefore, the work done by gravity is negative:

W_g = - F_g d

And substituting,

W_g=-(196)(0.02)=-3.92 J

(e) Zero

The net work done on the canister can be simply calculated by adding the work done by the tension in the cord and the weight of the canister:

W=W_T+W_g = 3.92 + (-3.92 ) = 0

This is in agreement with the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy. In this situation, the canister is moving at constant speed, so its kinetic energy is not change: therefore,

\Delta K = 0 (change in kinetic energy = 0)

and so, the work done on it is also zero.

(f) The pulley system changes the direction of the force applied

This is a simple pulley system, which means  that the system does not multiply the force applied in input. In fact, the mechanical advantage of the system is

MA=\frac{F_{out}}{F_{in}}

where:

F_{out} is the output force, which is the weight of the canister

F_{in} is the force in input, which is F

So, the mechanical advantage is 1:

MA=\frac{196 N}{196 N}=1

From a point of view of energy, therefore, there is no advantage in this system.

However, the advantage offered by the pulley system concerns the direction of the force: in fact, it changes the direction of the applied force (which is F, downward) into the tension of the cord (which is upward on the canister).

6 0
4 years ago
A 1022kg Caprice car stopped at an intersection is rear-ended by a 1620kg ranger truck moving with a speed of 14.5m/s. If the ca
Alika [10]

Answer:

Explanation:

mass of car, m = 1022 kg

mass of truck, M = 1620 kg

initial velocity of truck, U = 14.5 m/s

initial velocity of car, u = 0 m/s

Let the final velocity of car is v and the final velocity of truck is V.

Collision is elastic, so the coefficient of restitution, e = 1

Use conservation of momentum

initial momentum of car + initial momentum of truck = final momentum of car + final momentum of truck

m x u + M x U = m x v + M x V

0 + 1620 x 14.5 = 1022 v + 1620 V

23490 = 1022 v + 1620 V ..... (1)

Use the formula of coefficient of restitution

e = \frac{V_{1}-V_{2}}{u_{2}-u_{1}}

1 (14.5 - 0) = v - V

14.5 = v - V

V = v - 14.5 .... (2)

Put in equation (1)

23490 = 1022 v + 1620 (v - 14.5)

23490 = 1022 v + 1620 v - 23490

46980 = 2642 v

v = 17.8 m/s

Put in equation (2)

V = 17.8 - 14.5

V = 3.3 m/s

Thus, the speed of car is 17.8 m/s and the velocity of truck is 3.3 m/s after collision.

8 0
3 years ago
Will mark as brainliest if correct!!!!!
irakobra [83]

Refraction refers to C. the bending of light rays when they pass from one medium into another

Explanation:

Refraction is a phenomenon typical of wave. Refraction occurs when a wave travels through the boundary between two different mediums. When this occurs, the wave changes speed, wavelength and direction (but the frequency remains the same).

In particular, the direction of the refracted ray is determined by Snell's Law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1 is the index of refraction of the 1st medium

n_2 is the index of refraction of the 2nd medium

\theta_1 is the angle of incidence, which is the angle between the direction of the incident wave and the normal to the boundary

\theta_2 is the angle of refraction, which is the angle between the direction of the refracted wave and the normal to the boundary

Therefore, the correct description of refraction is

C. the bending of light rays when they pass from one medium into another

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

8 0
3 years ago
What quantity is represented by a unit called a newton (N)?
zavuch27 [327]

\textsf {C. Force}

\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}

5 0
2 years ago
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