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Sergeu [11.5K]
3 years ago
10

I’m on a test please help me

Physics
1 answer:
77julia77 [94]3 years ago
3 0
False.acceleration is change in distance
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The specification limits for a product are 8 cm and 10 cm. A process that produces the product has a mean of 9.5 cm and a standa
My name is Ann [436]

Answer:

The value of Cpk is 0.83.

Explanation:

Given that,

Upper specification limits = 10 cm

lower specification limits = 8 cm

Mean = 9.5

Standard deviation = 0.2 cm

We need to calculate the process capability

Using formula of Cpk

Cpk=min(\dfrac{USL-mean}{3\times SD}, \dfrac{mean-LSL}{3\times SD})

Put the value into the formula

Cpk=min(\dfrac{10-9.5}{3\times0.2}, \dfrac{9.5-8}{3\times0.2})

Cpk=min(0.83,2.5)

Cpk=0.83

Hence, The value of Cpk is 0.83.

4 0
3 years ago
Lakes
Nataliya [291]
I think is between A&B
I think I would answer B
6 0
3 years ago
water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49
vesna_86 [32]
When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
\theta = \arcsin ( \frac{n_2}{n_1} )
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}
6 0
4 years ago
What are four minerals that are commonly taken from ores
Umnica [9.8K]
If it helps or doesn't I'm sorry, but if you even played the game Minecraft just remember it. 

Gold, silver, coal, and iron come from ores. 
5 0
3 years ago
The force an ideal spring exerts on an object is given by Fx = -kx, where x measures the displacement of the object from its equ
shusha [124]

Answer:

The work done by this force can be found via the following formula

W = \int{F(x)} \, dx = \int\limits^0_{-20} {(-kx)} \, dx = \frac{-kx^2}{2}\left \{ {{x=0} \atop {x=-20}} \right. = \frac{-60*(-20)^2}{2} \\W = -12000J

Explanation:

Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

U = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2 =0 - \frac{1}{2}60(-20)^2 = -12000J

6 0
3 years ago
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