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Mama L [17]
3 years ago
11

Suppose you design a new thermometer called the "x" thermometer. on the x scale, the boiling point of water is 130.0 ox and the

freezing point of water is 10.0 ox. at what temperature will the readings on the fahrenheit scale and the x scale be the same?
Physics
1 answer:
Hoochie [10]3 years ago
6 0

You've told us:

-- 130°x  =  212°F

and

-- 10°x  =  32°F

Thank you.  Those are two points on a graph of °x vs °F .  With those, we can figure out the equation of the graph, and easily convert ANY temperature on one scale to the equivalent temperature on the other scale.

-- If our graph is going to have °x on the horizontal axis and °F on the vertical axis, then the two points we know are  (130, 212)  and  (10, 32) .

-- The slope of the line through these two points is

Slope = (32 - 212) / (10 - 130)

Slope = (-180) / (-120)

Slope = 1.5

So far, the equation of the graph is

F = 1.5 x + (F-intercept)

Plug one of the points into this equation.  I'll use the second point  (10, 32) just because the numbers are smaller:

32 = 1.5 (10) + F-intercept

32 = 15 + (F-intercept)

F-intercept = 17

So the equation of the conversion graph is

F = 1.5 x + 17

There you are !  Now you can plug ANY x temperature in there, and the F temperature jumps out at you.

The question is asking what temperature is the same on both scales. This seems tricky, but it's not too bad.  Whatever that temperature is, since it's the same on both scales, you can take the conversion equation, and write the same variable in BOTH places.

We can write [ x = 1.5x + 17 ], solve it for  x, and the solution will be the same temperature in  F  too.

or

We can write [ F = 1.5F + 17 ], solve it for  F, and the solution will be the same temperature in  x  too.

F = 1.5F + 17

Subtract  F  from each side:  0.5F + 17 = 0

Subtract 17 from each side:   0.5F = -17

Multiply each side by 2 :  F = -34

That should be the temperature that's the same number on both scales.

Let's check it out, using our handy-dandy conversion formula (the equation of our graph):

F = 1.5x + 17

Plug in -34 for  x:  

F = 1.5(-34) + 17

F = -51 + 17

<em>F = -34</em>

It works !  -34 on either scale converts to -34 on the other one too. If the temperature ever gets down to -34, and you take both thermometers outside, they'll both read the same number.

<em>yay !</em>

You might be interested in
How do you calculate Friction force without the coefficient of friction
nadezda [96]
Https://youtu.be/F_DEsMO_Wq8

hope this helped : )

3 0
3 years ago
Outside my window a squirrel is scurrying up and down a tree. Its position function is given by s(t) = t 3 − 12t 2 + 36t for the
marin [14]

Answer:

Explanation:

Given

Position of squirrel is given by

s(t)=t^3-12t^2+36t

Velocity is given by

v(t)=\frac{ds(t)}{dt}=\frac{d(t^3-12t^2+36t)}{dt}

v(t)=3t^2-12\times 2t+36

v(t)=3t^2-24t+36

(b) acceleration is given by

a(t)=\frac{da(t)}{dt}=\frac{d(3t^2-24t+36)}{dt}

a(t)=6t-24

(c)at s(3)=3^3-12(3)^2+36(3)

s(3)=27\ m

at s(4)=4^3-12(4)^2+36(4)

s(4)=16\ m

at t=3\ s Position is 27\ m and at t=4\ s position is 16\ m

therefore squirrel is moving down

6 0
3 years ago
Now, consider whether the following statements are true or false:_____________________________________.
Igoryamba

Answer:

A)F

B)F

C)T

Explanation:

A)

This is not always true that the product of the two vector's always non-negative .It may be positive or negative.

That is why this statement is false.

B)

The unit vectors in three perpendicular direction is i ,j and k.

We know that for unit vectors

i.i=j.j=k.k= 1

i .j= j.k=k.i=0

Therefore only  parallel component of the force will contribute in the integral part instead of perpendicular component of the force.

That is why this statement is false.

C)

This statement is True.

A)F

B)F

C)T

7 0
3 years ago
A 1.4-kg cart is attached to a horizontal spring for which the spring constant is 50 N/m . The system is set in motion when the
marin [14]

Answer:

A)

0.395 m

B)

2.4 m/s

Explanation:

A)

m = mass of the cart = 1.4 kg

k = spring constant of the spring = 50 Nm⁻¹

x = initial position of spring from equilibrium position = 0.21 m

v_{i} = initial speed of the cart = 2.0 ms⁻¹

A = amplitude of the oscillation = ?

Using conservation of energy

Final spring energy = initial kinetic energy + initial spring energy

(0.5) kA^{2} = (0.5) m v_{i}^{2} + (0.5) k x_{i}^{2} \\kA^{2} = m v_{i}^{2} + k x_{i}^{2} \\(50) A^{2} = (1.4) (2.0)^{2} + (50) (0.21)^{2} \\A = 0.395 m

B)

m = mass of the cart = 1.4 kg

k = spring constant of the spring = 50 Nm⁻¹

A = amplitude of the oscillation = 0.395 m

v_{o} = maximum speed at the equilibrium position

Using conservation of energy

Kinetic energy at equilibrium position = maximum spring potential energy at extreme stretch of the spring

(0.5) m v_{o}^{2} = (0.5) kA^{2}\\m v_{o}^{2} = kA^{2}\\(1.4) v_{o}^{2} = (50) (0.395)^{2}\\v_{o} = 2.4 ms^{-1}

5 0
3 years ago
Read 2 more answers
Please help! This is due in 10 minutes
Elenna [48]

Answer:

Atom - the basic particle of matter

Density - calculated from measurements of mass and volume

Motion - calculated from measurements of distance and time

Energy - can change form and move matter

Matter - the scientific word for <em>stuff</em>

<em />

Hope this helps! Please mark brainliest if correct :D

8 0
2 years ago
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