The solution for given linear equation systems is (3,-4).
Option: C
<u>Step-by-step explanation:</u>
The given equations are 5x+3y=3 and x+y= -1.
Let us isolate x value from equation 5x+3y=3.
5x = 3-3y.
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Substitute this x value in equation x+y= -1.
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After taking LCM for the denominator,
.
3-3y+5y=-5.
2y=-8.
y=-4.
For substitute the y value.
.
.
.
x=3.
∴ The solution is (3,-4).