What is the factored form of t6 − p3?

Mathematics

1 answer:

Mama L [17]3 years ago

4 0

Answer:

(C). (t² - p)( $t^{4}$ + pt² + p²)

Step-by-step explanation:

a³ - b³ = (a - b)(a² + ab + b²)

$t^{6}$ - p³ = (t²)³ - p³ = (t² - p)(  $t^{4}$  + pt² + p²)

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Factor Completely: 12x2 − 44x + 24 A) 2(2x − 6)(3x − 2) B) 4(x − 3)(3x − 2) C) 6(x − 4)(2x − 1) D) 12(x − 1)(x − 2)

Elan Coil [88]

Answer:

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Step-by-step explanation:

12x² - 44x + 24

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3 years ago

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3 years ago

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zhannawk [14.2K]

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5 0

2 years ago

Read 2 more answers

If (2i/2+i)-(3i/3+i)=a+bi, then a= A. 1/10 B. -10 C. 1/50 D. -1/10

Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

We need to find the value of a.

The LCM of (2+i) and (3+i) is (2+i)(3+i)

$=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}$

Now rationalize the denominator by multiplying by 5-5i/5-5i

$=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}$