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3 years ago

Please solve 4 terms???

Mathematics

2 answers:

Mars2501 [29]3 years ago

4 0

29 is the answer
Hope it helps

GalinKa [24]3 years ago

3 0

Answer:

Step-by-step explanation:

t1 = 10

t(n) = 3t_(n - 1) - 1

t(2) = 3*t(2 -1) - 1

t(2) = 3*t1 - 1

t(2) = 3*10 - 1

t_2= 30 - 1

t_2 = 29

t3 = 3*t2 - 1

t3 = 3*29 - 1

t3 = 87 - 1

t3 = 86

t4 = 3*t3 - 1

t4 = 3*86 - 1

t4 = 258 -1

t4 = 257

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3 years ago

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Step-by-step explanation:

☄ $\underline{ \underline{ \sf{Given}}}:$

Length ( l ) = 4 cm
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☄ $\underline{ \underline{ \sf{To \: find}}} :$

Total surface area of a cuboid

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$\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 76 \: {cm}}^{2} }}}$

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2 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

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Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

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