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7nadin3 [17]
2 years ago
7

Plz plz answer-------------------

Mathematics
2 answers:
Likurg_2 [28]2 years ago
8 0

Answer:

1.55

Step-by-step explanation:

trapecia [35]2 years ago
3 0

Answer:

1 11/20

Step-by-step explanation:

Sorry I don't have time to explain! Hope this helps and have a good day ^^

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There were 60 runners to start the race. In the first half of the race,1/3 of them dropped out. In the second half of the race,1
Verizon [17]
In the question, it is already given that the total number of runners in the race is 60 and out of them 1/3 dropped out in the first half. In the second half 1/4 of the remaining runners dropped out.
Now
Total number of runners in the race = 60
Number of runners that dropped out in the first half = 1/3 * 60
                                                                                   = 20
Number of runners remaining = 60 - 20
                                                 = 40
Number of runners dropping out in the second half = 40 * 1/4
                                                                                 = 10
Then the number of runners that finished the race = 40 - 10
                                                                                 = 30
Then 30 runners completed the race.
5 0
2 years ago
Read 2 more answers
THESE FRKN TEACHERS MAKE NO SENSE THEIR CLUELESS SOMEONE HELP AND JUST WRITE THE ANSWER ​ILL BRAINLLIST
SashulF [63]

Answer:

Whats F five is that a point or something???

Step-by-step explanation:

3 0
3 years ago
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Each of
vova2212 [387]

The median is 12.

The arithmetic mean is 12.7

The geometric mean is 11.3

4 0
3 years ago
Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma
Grace [21]

Given that x+y=1, we have y=1-x, so that

f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2

Take the derivative and find the critical points of g:

g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12

Take the second derivative and evaluate it at the critical point:

g''(x)=4>0

Since g'' is positive for all x, the critical point is a minimum.

At the critical point, we get the minimum value g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12.

5 0
2 years ago
I need some help finding m<B and the paper says that this isn't a right triangle so I can't use the Pythagorean theorem to fi
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3 years ago
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