A way to solve a linear system algebraically is to use the substitution method. ... We can substitute y in the second equation with the first equation since y = y.
this is what i know about it
There is no rate of change of Function 1. It's slope(rate of change) is zero.
Function 2 has a slope of 2.
The ratio is common, so you could write:
a1 * r^4 = a^5 (you do r^4 because there are 4 times you need to multiply by the ratio to get from a1 to a5)
Plug in the values:
3 * r^4 = 48
Divide by 3:
r^4 = 16
Take the fourth root of both sides:
r = 2
The common ratio is 2.
Right there 125677 on the left you go 4 ahhbsn
<u>Given</u><u> </u><u>:</u><u>-</u>
- To graph the line with slope 7 and y intercept -7.
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
Here since the slope of the line is 7 and y intercept is -7 , we can use the slope intercept form of the line to find the equation of the line . The slope intercept form of the line is ,
y = mx + c
On putting the respective values ,
y = 7(x) + (-7)
y = 7x - 7
<u>For</u><u> </u><u>the</u><u> </u><u>graph</u><u> </u><u>see </u><u>attachment</u><u> </u><u>.</u>