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3 years ago

A lent B rs 32500 to purchase a car at 12.5% p.A

Mathematics

1 answer:

LiRa [457]3 years ago

7 0

Answer:

6,483.75

Step-by-step explanation:

Calculation to find the interest paid by B after 3/2 year

First step is to calculate the Compound interest amountUsing this formula

Interest paid= P(1 + r/100)^Time

Where,

P represent principal=32,500

r represent Rate of interest = 12.5%/2 = 6.25%

T represent Time=3/2 years

Let plug in the formula

Compound interest amount= 32,500(1 + 6.25/100)^2*3/2

Compound interest amount= 32,500([1+.0625)^3

Compound interest amount= 32,500(1.0625)^3

Compound interest amount= 32,500 *1.1995

Compound interest amount= 38,983.75

Now let calculate the Interest paid by B

Interest paid by B = 38,983.75 - 32,500

Interest paid by B = 6,483.75

Therefore the interest paid by B after 3/2 year will be 6,483.75

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How many positive four-digit integers are multiples of 5 and less than 4,000

Volgvan

Answer:

Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

Explanation:

Lowest four digit positive integer = 1000

Highest four digit positive integer less than 4000 = 3999

We know that multiples of 5 end with 0 or 5 in their last digit.

So, lowest four digit positive integer which is a multiple of 5 = 1000

Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.

So, the numbers goes like,

1000, 1005, 1010 .....................................................3990, 3995

These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.

An = a + (n-1)d

3995 = 1000 + (n-1)x 5

(n-1) x 5 = 2995

(n-1) = 599

n = 600

So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

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