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3 years ago

The current theory of the structure of the

Physics

1 answer:

irina1246 [14]3 years ago

6 0

Answer:

pt 1: $m=1.66698*10^{21} kg$

Pt 2: $KE=1212.23531 J$

Explanation:

Information Given: (p = density)

l = 5200km d = 35km p = 2700kg/ $m^{2}$

Part 1: Mass

Find volume

$V=(l)^2(d)$
$V=(4.2*10^6)^2(35*10^3)$
$V=61.74*10^{16}$

Find Mass

$m=Vp$
$m=(61.74*10^{16})(2700)$
$m=1.66698*10^{21}$

Part 2: Kinetic Energy

$v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}$
$v=1.20497*10^{-9}$

$KE=\frac{1}{2}mv^2$

$KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2$

$KE=1212.23531 J$

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

$KE_{jogger}$

$KE=\frac{1}{2}mv^2$
$v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }$

Input the values

Hope it helps :)

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Which of the following is an example of the law of multiple proportions?

ser-zykov [4K]

The answer option which is an example of the law of multiple proportions is: B) Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

The Law of Multiple Proportions is also referred to as Dalton's Law and it states that when two chemical elements combine to form more than one chemical compound, the masses (weights) of one chemical element that combine with a fixed mass (weight) of the other chemical element will always be in a ratio of small whole numbers.

According to the Law of Multiple Proportions, when two chemical elements combine to form two different chemical compound, the masses (weights) of one chemical element that combine with 1 gram of the other chemical element can be expressed as a ratio of small whole numbers.

For example, carbon and oxygen react to form either carbon monoxide and carbon dioxide.

Carbon monoxide (CO):

12 grams of C = 16 grams of O.

1 gram of C = 1.33 gram of O.

Carbon dioxide ( $CO_2$ ):

12 gram of C = 32 grams of O.

1 gram of C = 2.66 gram of O.

Ratio of oxygen (O) = 16:32 = 1:2 (Law of Multiple Proportions).

Your question is lacking the necessary answer options, so I will be adding them here:

A. A sample of chlorine is found to contain three times as much Cl-35 as Cl-37.

B. Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

C. Two different samples of table salt are found to have the same ratio of sodium to chlorine.

D. The atomic mass of bromine is found to be 79.90 amu.

E. Nitrogen dioxide always has a mass ratio of 2.28 g O: 1 g N.

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2 years ago

While on the moon, the Apollo astronauts enjoyed the effects of a gravity much smaller than that on Earth. If Neil Armstrong jum

Juliette [100K]

Answer:

The gravitational acceleration experienced was of 1.63m/s².

Explanation:

We know, from the kinematics equations of vertical motion that:

$v^{2} =v_0^2-2gy$

Solving for g, we get:

$g=-\frac{v^2-v_0^2}{2y}$

Since the final speed is zero, because Neil Armstrong came to a stop in his maximum height, we obtain:

$g=\frac{v_0^2}{2y}$

Finally, we plug in the given values of the initial speed and the maximum height:

$g=\frac{(1.51m/s)^2}{2(0.700m)}=1.63m/s^2$

This means that the gravitational acceleration experienced by Neil Armstrong in the moon, was of 1.63m/s².

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3 years ago

A(n) 930 N crate is being pushed across a level floor by a force of 400 N at an angle of 20◦ above the horizontal. The coefficie

Nana76 [90]

Answer:

The magnitude of the acceleration of the box is $2.291\,\frac{m}{s^{2}}$ .

Explanation:

The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:

$\Sigma F_{x} = P\cdot \cos 20^{\circ} - \mu_{k}\cdot N = \left(\frac{W}{g}\right)\cdot a$

$\Sigma F_{y} = P\cdot \sin 20^{\circ} + N - W = 0$

From second equation of equilibrium we find an expression for the normal force and find the respective value:

$N = W - P \cdot \sin 20^{\circ}$

$N = 930\,N - 400\cdot \sin 20^{\circ}\,N$

$N = 793.192\,N$

Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:

$a = \frac{P\cdot \cos 20^{\circ}-\mu_{k}\cdot N}{\frac{W}{g} }$

$a = \frac{400\cdot \cos 20^{\circ}\,N-0.20\cdot (793.192\,N)}{\frac{930\,N}{9.807\,\frac{m}{s^{2}} } }$

$a = 2.291\,\frac{m}{s^{2}}$

The magnitude of the acceleration of the box is $2.291\,\frac{m}{s^{2}}$ .

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3 years ago

What is the kinetic energy of a 2000 kilogram boat moving at 5m/sec?

Tanya [424]

Hello!
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3 years ago

In order for a length of copper wire or a loop of copper wire to have a magnetic field, what must they have flowing through them

Nataliya [291]

Electricity.
When electricity flows through wire (such as a battery circuit) it creates a magnetic field around the wire.

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4 years ago