Answer:
728 N
Explanation:
= length of the wire = 0.680 m
= mass of the steel wire = 0.0046 kg
= Fundamental frequency = 261.6 Hz
= tension force in the steel wire
Fundamental frequency in wire is given as
![f = \frac{1}{2L} \sqrt{\frac{TL}{m} } \\261.6 = \frac{1}{2(0.680)} \sqrt{\frac{T(0.80)}{0.0046} }\\(2) (0.680) (261.6) = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8 = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8^{2} = \frac{T(0.80)}{0.0046}\\T = \frac{(355.8^{2}(0.0046))}{0.80} \\T = 728 N](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2L%7D%20%5Csqrt%7B%5Cfrac%7BTL%7D%7Bm%7D%20%7D%20%5C%5C261.6%20%3D%20%5Cfrac%7B1%7D%7B2%280.680%29%7D%20%5Csqrt%7B%5Cfrac%7BT%280.80%29%7D%7B0.0046%7D%20%7D%5C%5C%282%29%20%280.680%29%20%28261.6%29%20%3D%20%5Csqrt%7B%5Cfrac%7BT%280.80%29%7D%7B0.0046%7D%20%7D%5C%5C355.8%20%3D%20%5Csqrt%7B%5Cfrac%7BT%280.80%29%7D%7B0.0046%7D%20%7D%5C%5C355.8%5E%7B2%7D%20%3D%20%5Cfrac%7BT%280.80%29%7D%7B0.0046%7D%5C%5CT%20%3D%20%5Cfrac%7B%28355.8%5E%7B2%7D%280.0046%29%29%7D%7B0.80%7D%20%5C%5CT%20%3D%20728%20N)
Tensional forces which is associated with normal faults
Mass extinction occur from natural disasters, such as a n asteroid hitting earth or a volcano errupting and spread ash everywhere.
It makes sense to measure geologic time between mass extinctions because after each mass extinction, there is almost no life left and the few left have to repopulate, which may lead way to new mutations and new varieties of plants and animals.
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The energy of the system is E=5.5 J. This energy is the same at every moment of the oscillation. When the stretch x of the spring is maximum (so, when the stretch is equal to the amplitude: x=A) the velocity of the spring is zero, so all this energy is just elastic potential energy of the spring:
![E= \frac{1}{2}kA^2](https://tex.z-dn.net/?f=E%3D%20%5Cfrac%7B1%7D%7B2%7DkA%5E2%20)
From which we find