I’m going to use molasses as an example of a substance.
The mass and volume both change when changing the amount of molasses.
However, the density does not change. This is because the mass and volume increase at the same rate/proportion!
Even though there is more molasses (mass) in test tube A, the molasses also takes up more space (volume). Therefore, the spacing between those tiny particles that make up the molasses is constant (does not change).
The size or amount of a material/substance does not affect its density.
Maps and Globes share the following features:
Both are scale Models.
Explanation:
A globe is a scale model of the Earth that presents the most accurate depiction of geographic information such as area, distance, and direction.
A map is a two dimensional representation or a drawing of the earth’s surface, or a part of it, on a flat surface, according to a scale. Thus it is also a scale model.
A globe differs from a map. It is a three dimensional sphere representing the whole Earth.
A map is usually used to represent a specific part of the Earth and is used for Navigation. It has details and symbols. However, a globe can not be used for such details.
A globe can be used to get a broad-level picture of the world.
Keywords: geography, earth, maps, globes
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Volume by Displacement. The displacement method (submersion, or dunking method) can be used to accurately measure the volume of the human body and other oddly shaped objects by measuring the volume of fluid displaced when the object is submerged.
The following precautions should be taken very observantly:-
The line of sight must be perpendicular to measuring scale to avoid parallax error. Formation of bubbles inside the cylinder should be completely avoided. Any bubbles within leads to wrong measurements.
Refer to the figure below.
R = resistance.
Case 1:
The voltage source is V₁ and the current is 10 mA. Therefore
V₁ = (10 mA)R
Case 2:
The voltage source is V₂ and the current is 8 mA. Therefore
V₂ = (8 mA)R
Case 3:
The voltage across the resistance is V₁ - V₂. Therefore the current I is given by
V₁ - V₂ = IR
10R - 8R = (I mA)R
2 = I
The current is 2 mA.
Answer: 2 mA