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Black_prince [1.1K]
3 years ago
8

Which set of a side lengths can be used to form a right angle?

Mathematics
1 answer:
Rashid [163]3 years ago
4 0

Answer:

Any of the Pythagorean Triples

Step-by-step explanation:

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F(x)=1/2×+6 plz helpppppppppp​
FromTheMoon [43]

Answer:

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

Step-by-step explanation:

Given function:

f(x)=\frac{1}{2x+6}

To find the domain of the function in set notation.

Solution:

For the function f(x) to exist the denominator must be ≠ 0

We have the denominator (2x+6) which  cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function f(x) will not exist when:

2x+6=0

Solving for x

Subtracting both sides by 6.

2x+6-6=0-6

2x=-6

Dividing both sides by 2.

\frac{2x}{2}=\frac{-6}{2}

∴ x=-3

Thus, the function will not exist at x=-3. This means it has all real number solutions except -3.

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

3 0
3 years ago
Use the definition of the derviative to compute the derivative of f(x)= 1- 7x^2 at the specific point x=2.
GaryK [48]

Answer:

f'(x) = -28 \ at  \ x = 2

Step-by-step explanation:

f'(2) =  \lim_{h \to 0}\frac{f(2+h)) -f(2)}{h} \\\\f(2+h) = 1 - 7(2+h)^2 = 1 - 7(4 +h^2 +4h) = 1 - 28 - 7h^2 - 28h = - 7h^2 -28h - 27\\\\f(2) = 1 - 7(2^2) = 1 - 28 = -27\\\\f(2+h) - f(2) = -7h^2 - 28h - 27 - (-27) = -7h^2 -28h -27 + 27 = -7h^2 -28h\\\\f'(2) =   \lim_{h \to 0}\frac{-7h^2 - 28h}{h} \\\\

       = \lim_{h \to 0} \frac{h(-7h -28)}{h}\\\\= \lim_{h \to 0} (-7h -28)}\\\\= -7 (0) - 28\\\\= -28

4 0
3 years ago
Find a quadratic function in standard form for each set of points
otez555 [7]
For 1 the equation of the parabola is y = x^2 - 8x + 3
For 2 the equation of the parabola is y = -2x^2 - 3x + 1
For 3 the equation of the parabola is y = -x^2 + 5x - 4
5 0
3 years ago
Im having trouble. can someone please help me with this !
VladimirAG [237]

Answer:

28

Step-by-step explanation:

5 0
3 years ago
Let p = log10 x, q = log10 y, and r = log10 z. (The 10s are base numbers.)
KatRina [158]

Answer:

(p / q^2 √r)

Just make x, y, z into p, q, r.

Very simple!

4 0
3 years ago
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