Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17
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For this case, the main function is given by:
We can apply the following transformation:
Horizontal displacements:
Assume h> 0:
To graph f (x + h) move the graph of f (x) h units to the left.
For h = 1 we have:
Answer:
the graph y=6(x+1)^2 is the graph y=6x^2 moved 1 unit to the left.