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luda_lava [24]
3 years ago
8

Find the domain and range of the function below

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0
X is greater than or equal to 0
y is greater than or equal to 0
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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)
Pie

Answer:

The ratio of AC/CB=1/3

Step-by-step explanation:

We use the section formula:

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n})

This is supposed to be equal to: (0,2).

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)

We can equate, corresponding coordinates to find m and n.

\frac{4.5m - 1.5n}{m + n}  = 0

This implies that:

4.5m - 1.5n = 0

4.5m  = 1.5n

\frac{m}{n}  =  \frac{1.5}{4.5}

\frac{m}{n}  =  \frac{1}{3}

Therefore the ratio is m:n=1:3

4 0
3 years ago
What are the dimensions of a rectangular box with a volume of 50b 3 + 75b2 - 2b - 3?
Inessa [10]

Answer:

\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}

Step-by-step explanation:

The formula of a volume of a rectangular box:

V=lwh

<em>l</em><em> - lenght</em>

<em>w</em><em> - width</em>

<em>h</em><em> - height</em>

V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)

Therefore the dinemsions of thisp prism are:

(2b+3)\times(5b-1)\times(5b+1)

5 0
3 years ago
Read 2 more answers
What is the simplified fraction of 30/48 using the giant one<br>​
STatiana [176]

Answer:

The answer is

\frac{30}{48}  =  \frac{15}{24}

4 0
3 years ago
Read 2 more answers
Find the area of the shaded region (in the photo and step by step response please)
irina1246 [14]

Step-by-step explanation:

Area of shaded =Area of Outer rectangle - Area of Inner rectangle.

Area of inner rectangle = L× B.

L=18

B=11

Area of inner rectangle = 18×11

=198m^2

To find the full breadth of the outer rectangle

=2 in +11 + 2 in

=15

To find the full length of the outer rectangle

=2 in + 18 + 2 in

=22

Area= 22 × 15

Area = 330m^2

Area of shaded portion = 330 - 198

=132m^2

3 0
3 years ago
Helpppppppppppppppppp asap thanks
Ira Lisetskai [31]
For this case we have the following vertices:
 D = (- 1, -1)
 E = (1, -1)
 F = (- 1, -6)
 Then, the vertices after the transformation are:
 D '= (- 1, 1)
 E '= (1,1)
 F '= (- 1,6)
 The x coordinate remains the same
 The y coordinate change sign.
 Therefore, the transformation is:
 Reflection on the x axis.
 Answer:
 
Reflection on the x axis.
 
option 1
5 0
3 years ago
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