We are to show that the given parametric curve is a circle.
The trajectory of a circle with a radius r will satisfy the following relationship:
(with (x_c,y_c) being the center point)
We are given the x and y in a parametric form which can be further rewritten (using properties of sin/cos):
Squaring and adding both gives:
The last expression shows that the given parametric curve is a circle with the center (0,0) and radius A.
Answer:
1.776 x 10^-19 m
Explanation:
Energy, E = 7 TeV
Let λ be the wavelength.
Energy = h c / λ
Where, h is the Planks,s constant and c be the velocity of light
h = 6.63 x 10-^-34 Js
c = 3 x 10^8 m/s
Convert TeV into J
1 TeV = 1.6 x 10^-7 J
So, E = 7 x 1.6 x 10^-7 = 11.2 x 10^-7 J
11.2 x 10^-7 = (6.63 x 10^-34 x 3 x 10^8) / λ
λ = 1.776 x 10^-19 m
Answer:
Explanation:
We know that , for an object to remain in circular motion , a force towards centre is required which is called centripetal force. In the circular motion of
satellites around planet , this force is provided by the gravitational attraction between satellite and planet.
If M be the mass of planet and m be the mass of satellite, G be gravitational constant and R be the distance between planet and satellite or R be the radius of orbit
Gravitational force = G Mm / R²
If v be the velocity with which satellite is orbiting
centripetal force
= m v² /R
Centripetal force = gravitational attraction
m v² /R = G Mm / R²
v =
Time period = time the satellite takes to make one rotation
= distance / orbital velocity
= 2πR/ v
=
T =
External force.
Air resistance, friction, grass rubbing on a rolling ball, etc.
If there is no external force on a moving object, it keeps going.
Forever !
Theyre all in constant motion