Answer:
time rising = 34 / 9.8 = 3.47 sec
total time in air = 2 * 3.47 sec = 6.94 sec
(time rising must equal time falling)
R = 17 m/s * 6.94 s = 118 m
Can also use range formula
R = v^2 sin (2 theta) / g
tan theta = 34 / 17 = 2
theta = 63.4 deg
2 theta = 126.9 deg
sin 126.9 = .8
v^2 = 17^2 + 34^2 = 1445 m^2/s^2
R = 1445 * .8 / 9.8 = 118 m agreeing with answer found above
Answer:
86.6 lbs
Explanation:
Let the force is X.
Resultant force, R = 100 lbs
Other force is Y. Angle between resultant force and force X is 30°.
According to the diagram
X = 86.6 lbs
Other force Y
Y = 50 lbs
Because your brain cant handle all of the information.
Answer:
shock, tremble, fault, slip, temblor, upheaval, trembler
undulation
macroseism
seimicity
seismism
Explanation:
Answer:
Explanation:
An object is thrown up from a height of 520m
h_o = 520m
Initial velocity of thrown is 18m/s
u = 18m/s
What is the position of the object after 3seconds
t = 3s
Acceleration due to gravity
g = 9.81 m/s²
Let calculated the height the object will reached when thrown from the top.
Using equation of motion
h = ut + ½gt²
Since the body is thrown upward, it is acting against gravity then, gravity will be negative
Then,
h = ut — ½gt²
h = 18 × 3 — ½ × 9.81 × 3²
h = 54 — 44.145
h = 9.855 m
So, the body is above the top of the building at a distance of 9.855m
So, the total distance from the bottom is
Position = h + h_o
x = 9.855 + 520
x = 529.855m
x ≈ 530m,
The position of objects after 3seconds is 520m
