Answer: 7.53 μC
Explanation: In order to explain this problem we have to use the gaussian law so we have:
∫E.dS=Qinside/εo we consider a gaussian surface inside the conducting spherical shell so E=0
Q inside= 0 = q+ Qinner surface=0
Q inner surface= 1.12μC so in the outer surface the charge is (8.65-1.12)μC=7.53μC
125 because f=ma so you would use 100=mx0.75
Answer:
, 
Explanation:
The acceleration of the plane can be determined by means of the kinematic equation that correspond to a Uniformly Accelerated Rectilinear Motion.
(1)
Where
is the final velocity,
is the initial velocity,
is the acceleration and
is the distance traveled.
Equation (1) can be rewritten in terms of ax:
(2)
Since the plane starts from rest, its initial velocity will be zero (
):
Replacing the values given in equation 2, it is gotten:




So, The acceleration of the plane is
Now that the acceleration is known, the next equation can be used to find out the time:
(3)
Rewritten equation (3) in terms of t:



<u>Hence, the plane takes 26.92 seconds to reach its take-off speed.</u>
Answer:
R= 5.4 ohms
Explanation:
Given that
V= 9 V
Power ,P= 15 W
Lets take resistor resistance = R
We know that Power given as

V=Voltage
P=Power
R=Resistance

Now by putting the all the values in the above equation

R= 5.4 ohms
Therefore the resistance of the resister will be 5.4 ohms.