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Liula [17]
2 years ago
11

Help. Science is getting on my nerves

Physics
2 answers:
anyanavicka [17]2 years ago
8 0
The correct answer is the First choice
NISA [10]2 years ago
7 0
Both objects must have mass
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What happens in the crushing can experiment?
Dafna1 [17]

Explanation:

When hot water is poured on the can in a bucket of cold water, the can crushes off means it gets unshaped

7 0
3 years ago
A particle moves along the x axis so that its velocity at time t is given by v(t)=
vodomira [7]

Answer:

a = 0.7267 ,  acceleration is positive therefore the speed is increasing  

Explanation:

The definition of acceleration is

         a = dv / dt

they give us the function of speed

         v = - (t-1) sin (t² / 2)

         a = - sin (t²/2) -  (t-1) cos (t²/2)  2t / 2

         a = - sin (t²/2) - t (t-1)  cos (t²/2)

the acceleration for t = 4 s

          a = - sin (4²/2) - 4 (4-1) cos (4²/2)

          a = -sin 8 - 12 cos 8

remember that the angles are in radians

          a = 0.7267

the problem does not indicate the units, but to be correct they must be m/s²

We see that the acceleration is positive therefore the speed is increasing

6 0
2 years ago
Which planet is least like earth? Mars,Venus, or Jupiter
Brums [2.3K]

Answer:

mars, reason why is because they both are diff from the size

Explanation:

7 0
3 years ago
Read 2 more answers
A rocket travels from the moon to earth, describe how its weight changes during the journey.
Vladimir79 [104]

Answer:

It has to overcome earth's gravity and have enough fuel to land on the moon at a slow enough speed

7 0
3 years ago
Interactive Solution 9.37 presents a method for modeling this problem. Multiple-Concept Example 10 offers useful background for
viva [34]

Answer:

21.67 rad/s²

208.36538 N

Explanation:

\omega_f = Final angular velocity = \dfrac{1}{6}78=13\ rad/s

\omega_i = Initial angular velocity = 78 rad/s

\alpha = Angular acceleration

\theta = Angle of rotation

t = Time taken

r = Radius = 0.13

I = Moment of inertia = 1.25 kgm²

From equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{13-78}{3}\\\Rightarrow \alpha=-21.67\ rad/s^2

The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=1.25\times -21.67\\\Rightarrow \tau=-27.0875

Frictional force is given by

F=\dfrac{\tau}{r}\\\Rightarrow F=\dfrac{-27.0875}{0.13}\\\Rightarrow F=-208.36538\ N

The magnitude of the force of friction applied by the brake shoe is 208.36538 N

5 0
3 years ago
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