The empirical formula of the alcohol is C₄H₄O
To solve the question given above, we'll begin by calculating the percentage of oxygen in the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
<h3>Oxygen (O) =? </h3>
O = 100 – (C + H)
O = 100 – (70.57 + 5.935)
O = 100 – 76.505
<h3>O = 23.495%</h3>
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
Oxygen (O) = 23.495%
<h3>Empirical formula =?</h3>
Divide by their molar mass
C = 70.57 / 12 = 5.881
H = 5.935 /1 = 5.935
O = 23.495 / 16 = 1.468
Divide by the smallest
C = 5.881 / 1.468 = 4
H = 5.935 / 1.468 = 4
O = 1.468 / 1.468 = 1
Therefore, the empirical formula of the alcohol is C₄H₄O
Learn more: brainly.com/question/19667938
Answer:
Not sure were to start....
Explanation:
Your answer would be C. Potential energy is when your withholding the action and are about to carry through with the action
The given statement is false.
In physics, a quantum (plural quanta) is the minimum amount of any bodily entity (physical property) concerned in an interaction. The vital thinking that a bodily property can be "quantized" is referred to as "the speculation of quantization".[1] This capability that the magnitude of the bodily property can take on only discrete values consisting of integer multiples of one quantum.
Learn more about quantum here:
brainly.com/question/16977590
#SPJ4
Answer:
Plasma
Explanation:
Plasma is a state of matter that in some cases is a synonym of ionized gas. It consists of groups of ions (particles with a net charge) with some of their outer electrons removed.
How many electrons have been removed depends on the type of plasma, since the most energetic plasmas are completely free of orbiting electrons. This is the case of the interiors of the sun and other stars.