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Andreyy89
4 years ago
13

The equilibrium fraction of lattice sites that are vacant in silver (ag) at 500°c is 0.5 x 10-6. calculate the number of vacanci

es (per meter cubed
Chemistry
1 answer:
Sedbober [7]4 years ago
6 0
Missing question: <span>Assume a density of 10.35 g/cm3 for Ag, A(Ag) = 107.87 g/mol.
N(Ag) = Na </span>· d(Ag) ÷ A(Ag).
N(Ag) = 6,023·10²³ atoms/mol · 10,35 g/cm³ · 10⁶ cm³/m³ ÷ 107,87 g/mol.
N(Ag) = 5,78·10²⁸ atoms/mol.
Nv = 5,78·10²⁸ atoms/mol · 5·10⁻⁵.
Nv = 2,89·10²².
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The combustion of caffeine with the molecular masses is given below. If you have 0.150 grams of caffeine, how much NO2 in grams
lord [1]

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

8 0
3 years ago
Determine the mass in grams of 5.00 mol of oxygern. the molar mass of oxygen is 16. g/mol
maks197457 [2]

Answer:

80 grams

Explanation:

number of moles=mass/molar mass .

5=x/16, x=16*5

x=80 grams

6 0
3 years ago
When water vapor is cooled from 250°c to 150°c in a rigid tank the vapor just starts to?
viktelen [127]
The water vapor will begin to contract. The particles will begin to bond with each other to seek heat so they're contracting.
3 0
4 years ago
Using the Fick equation, calculate cardiac output if a person is consuming 1.41 L O2/min, has an arterial O2 content of 190 ml O
Elden [556K]

Answer:

Cardiac output (CO) = 8.54 l / min

Explanation:

Given:

Oxygen consumption (V) = 1.41 l O2/min

Oxygen in arterial (Ca) = 190 ml O2/L = 0.19 l O2/L

Oxygen in venous (Cv) = 25 ml O2/L = 0.025 l O2/L

Find:

Cardiac output (CO)

Computation:

Cardiac output (CO) = V / (Ca - Cv)

Cardiac output (CO) = 1.41 / (0.19 - 0.025)

Cardiac output (CO) = 8.54 l / min

8 0
3 years ago
what is the equation relating to the energy separation between levels in the H atom to the number of the level (n) called?​
Firlakuza [10]

Answer:  https://study.com/academy/answer/complete-the-sentence-concerning-the-energy-level-diagram-for-the-hydrogen-atom-the-equation-relating-the-energy-separation-between-levels-in-the-h-atom-to-the-number-of-the-level-n-is-called-the-equation.html#:~:text=Answer%20and%20Explanation%3A,is%20called%20the%20Bohr's%20equation.

Bohr's equation

Explanation:  https://study.com/academy/answer/complete-the-sentence-concerning-the-energy-level-diagram-for-the-hydrogen-atom-the-equation-relating-the-energy-separation-between-levels-in-the-h-atom-to-the-number-of-the-level-n-is-called-the-equation.html

Answer and Explanation: The equation relating the energy separation between levels in the H atom to the number of the level (n) is called the Bohr's equation.

6 0
3 years ago
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