Answer:
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Explanation:
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In the reaction, Na⁺ + 6H₂O ⇆ Na (H₂O)⁺₆, Na⁺ is a Lewis acid and H₂O is a Lewis base.
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What is a Lewis acid-base reaction?</h3>
- According to the Lewis theory of acid-base reactions, acids accept pairs of electrons and bases donate pairs of electrons.
- Any substance like H+ ion, which is capable of accepting a pair of nonbonding electrons or an electron-pair acceptor is known as a Lewis acid.
- Any substance, like the OH- ion, that is capable of donating a pair of nonbonding electrons or an electron-pair donor is a Lewis base.
- Here Na⁺ that is electron deficient accepts electrons from the electron donor, H₂O
- From the Lewis theory, with no change in the oxidation numbers of any atoms, acids react with bases to share a pair of electrons.
To learn more about Lewis acid-base reactions: brainly.com/question/14861040
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Answer:
177.1 L
Explanation:
The excersise can be solved, by the Ideal Gases Law.
P . V = n . R . T
In first step we need to determine the moles of gas:
We convert T° from, C° to K → 20°C + 273 = 293K
We convert P from mmHg to atm → 760 mmHg = 1atm
1Dm³ = 1L → 190L
We replace: 190 L . 1 atm = n . 0.082 . 293K
(190L.atm) / 0.082 . 293K = 7.91 moles.
We replace equation at STP conditions (1 atm and 273K)
V = (n . R .T) / P
V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L
We can also make a rule of three:
At STP conditions 1 mol of gas occupies 22.4L
Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L
1) Ca-37, with a half-life of 181.1(10) ms.
