Answer: A = y/cos32
That is the amplitude A in terms of the displacement y.
Explanation: Since the displacement in the question In the question is the same in both direction, it is a Simple Harmonic Motion problem. In s.h.m the amplitude of displacement A is related to the displacement itself y by this simple equation
y = A* cos(theta)
So, A = y/cos(theta)
A = y/cos32.
If the magnitude of the displacement y is given, you just substitute in.
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The shades are very different
if the color changes, it is neutral but if it stays the same, it is an acid.
The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s
<h3>What are the components of velocity?</h3>
We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.
Hence;
Vertical component = 40 m/s sin 15 degrees = 10.35 m/s
Horizontal component = 40 cos 15 degrees = 38.6 m/s
Learn more about components of velocity:brainly.com/question/14478315
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