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2 years ago

Which sentence correctly uses a comma to separate coordinate adjectives?

Physics

1 answer:

lubasha [3.4K]2 years ago

6 0

Answer:

Explanation:

Coordinate adjectives are adjectives that describe the same noun equally. They should be separated with commas. In this sentence, both red and round are describing the ball. The correct answer is, "The red, round ball is Adley's favorite toy to play with."

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3 years ago

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The weight of an object _____.

denis23 [38]

The weight of an object is the force with which it is attracted to earth. The gravity of an object or body of an object is high on earth than at the atmosphere. It has an average of gravitational constant equal to 9.8066 or 9.8 meters per second. In truth, the acceleration of the object depend upon its location, the latitude and altitude, on earth.

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A loop of wire is placed in a uniform magnetic field. (a) For what orientation of the loop is the magnetic flux a maximum? The p

ra1l [238]

Answer:

1) The plane of the loop is perpendicular to the magnetic field.

2) The magnetic flux is independent of the orientation of the loop.p

Explanation:

The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.

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3 years ago

Two small plastic spheres are given positive electrical charges. When they are a distance of 14.8cm apart, the repulsive force b

sdas [7]

Answer:

Explanation:

Case I: They have same charge.

Charge on each sphere = q

Distance between them, d = 14.8 cm = 0.148 m

Repulsive force, F = 0.235 N

Use Coulomb's law in electrostatics

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

By substituting the values

$0.235=\frac{9\times10^{9}q^{2}}{0.148^{2}}$

$q=7.56\times10^{-7}C$

Thus, the charge on each sphere is $q=7.56\times10^{-7}C$ .

Case II:

Charge on first sphere = 4q

Charge on second sphere = q

distance between them, d = 0.148 m

Force between them, F = 0.235 N

Use Coulomb's law in electrostatics

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

By substituting the values

$0.235=\frac{9\times 10^{9}\times 4q^{2}}{0.148^{2}}$

$q=3.78\times10^{-7}C$

Thus, the charge on second sphere is $q=3.78\times10^{-7}C$ and the charge on first sphere is $4q = 4\times 3.78\times 10^{-7}=1.51 \times 10^{-6} C$ .

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4 years ago

Two diamonds begin a free fall from rest and from the same height 1 second apart.

Bumek [7]

Answer:

Explanation:

let t be time since the second diamond is released

a) y = ½g(t + 1)²

b) y' = ½g(t)²

25 = ½g(t + 1)² - ½gt²

25 = ½g(t² + 2t + 1) - ½gt²

25 = ½gt² + gt + ½g - ½gt²

25 = g(t + ½)

t + ½ = 25 / g

t = (25 / g) - ½

t = (25 / 9.8) - ½

t = 2.05102... ≈ 2.1 s

6 0

3 years ago