Answer: the probability that during a randomly selected month, PCE's were between $775.00 and $990.00 is 0.9538
Step-by-step explanation:
Since the amount that the company spent on personal calls followed a normal distribution, then according to the central limit theorem,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
From the information given,
µ = $900
σ = $50
the probability that during a randomly selected month PCE's were between $775.00 and $990.00 is expressed as
P(775 ≤ x ≤ 990)
For (775 ≤ x),
z = (775 - 900)/50 = - 2.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.0062
For (x ≤ 990),
z = (990 - 900)/50 = 1.8
Looking at the normal distribution table, the probability corresponding to the z score is 0.96
Therefore,
P(775 ≤ x ≤ 990) = 0.96 - 0.0062 = 0.9538
47 = 50 - 3 or:
47 = Mean - 1 Standard deviation
For normal distribution it means that 4 bags represent 16 % of all samples.
4 bags ------ 16%
x bags ------ 100 %
---------------------------
4 * 100 = x * 16
16 x = 400
x = 400 : 16
x = 25
Answer: 25 bags were probably taken as samples.
multiply the tops and bottoms, so:
1 * -5 * 3 = -15 for top
and
5 * 7 * 4 = 140 for bottom
then reduce by dividing by 5, and you get:
-3/28
Answer:
12.496
Step-by-step explanation: