Answer: 24ways
Step-by-step explanation:
Given data:
No of men in the workplace = 7
No of women in the workplace = 1
How many ways can a group of 4 people carry out a project if on out of the 3 must be a woman.
Solution.
A group of 4 can carry out the project with one be a woman
This means there must be 3 males and 1 female in the group
= 4p3
= 24ways
The project can be carried out by 4 groups in 24 ways
Two or zero expresses the possible number of positive real solutions for the given polynomial equation.
Answer: Option D
<u>Step-by-step explanation:</u>
Given equation:
First, we put hit and trial method to find out the one solution. So, if we put x=4 then the above expression will become zero. We can also write the above expression as
We know the formula, , make use of this, we get
So,
Hence, from the above expression, we have three values of x as x= 4, 2.64 and -2.64
First chore, 6 to choose from.
Second chore, 5 to choose from.
Third chore, 4 to choose from.
Fourth chore, 3 to choose from.
Fifth chore, 2 to choose from.
Sixth chore, 1 to "choose" from.
The total number of orders possible is the product
6*5*4*3*2*1=6!=720
Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.