To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration
of the stock solution, V1 is the volume of the stock solution, M2 is the
concentration of the new solution and V2 is its volume.
2 M x V1 = 0.1 M x .5 L
<span>V1 = 0.025 L or 25 mL of the
2 M KCl solution is needed</span>
Answer:
4
Explanation:
Applying,
pH = 14-pOH.................... Equation 1
But,
pOH = -log(OH⁻)
Where OH⁻ = Hydroxyl ion concentration of NaOH.
From the question,
Given: OH⁻ = (1×10⁻¹⁰) M
Substitute these values into equation 1
pH = 14-log((1×10⁻¹⁰)
pH = 14-10
pH = 4
Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4
B!
“Wind is the movement of air caused by the uneven heating of the Earth by the sun.” Source: National Geographic
Reactant: <span>Cd(NO^3)^2+(aq)+H^2S(g)
</span>Product: <span>Cds(s)+2HNO^3(aq)</span>
net ionic equation
B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
Explanation:
We have the following chemical equation:
2 Na⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 Cl⁻ (aq) → 2 Na⁺ (aq) + 2 Cl⁻ (aq) + BaSO₄ (s)
To get the net ionic equation we remove the spectator ions and we get:
SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
were:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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